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v^2=u^2 + 2as (3rd equation of motion) where v=final velocity (0); u = initial velocity; a=acceleration (-10 m/s^2) and s=distance (320m). So u^2 = 2as = 2 x 320 x 10 = 6400. This gives u = 80 m/s

3 Answers · Science & Mathematics · 12/09/2006

For a solid sphere, I = (2/5)mr² and rotational KE = ½Iω² = ½ * (2/5)mr² * (v/r)² = (1/5)mv² So: translational KE = ½ * 7.1kg * (4.6m/s)² = 75 J rotational KE = (1/5...

2 Answers · Science & Mathematics · 09/11/2013

1 meter. .

2 Answers · Science & Mathematics · 18/12/2010

(a) translational kinetic energy = (1/2)*m*(v^2) =(1/2)*10*(10^2) =500J (b) rotational kinetic energy =(1/2)*I*(w^2) w-angular velocity(omega), I-moment of inertia =(1/2)*(2/5*m*r^2)(w^2...

2 Answers · Science & Mathematics · 24/12/2012

960mph. lol jk

2 Answers · Science & Mathematics · 10/08/2008

Don't forget to supply what units you are working with! (342 + 24.5) = apparent V of 366.5m/sec. a) (366.5/342) x 400 = 428.655Hz. b) 428.655Hz.

2 Answers · Science & Mathematics · 30/01/2013

average v = (0 + 340) / 2 = 170 m/s Time in the barrel t = 0.85 / average v = 0.85 / 170 = 0.005 a = dv / dt = 340 / 0.005 = 68000 m/s2 force exerted on the rifle by the bullet F = m * a = 20 10^-3 * 68 10^3 = 1360 N Goodbye

1 Answers · Science & Mathematics · 13/02/2013

These are all very simple physics questions, and are quite obviously from homework or something of the like. Here are the equations you'll need to solve them: F = ma Fc = mv^2/r Where F is force...

1 Answers · Science & Mathematics · 06/07/2012

(a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

1 Answers · Science & Mathematics · 24/06/2016

OK, simple V=D/T. Velocity = Distance/Time D = 2 x pi x r . T (in seconds) is 23.9 x 3600 (seconds in an hour) Since everything is nice an linear - the R for part be needs to be 1/3 of...

1 Answers · Science & Mathematics · 04/07/2013

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