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  1. g = - 10 (It's going down. vi = 20 m/s t = 1 second vf = ???? g = (vf - vi)/t -10 = (vf - 20)/1 -10 = vf - 20 10 = vf This means it is still going up and the speed is 10 m/s up -10 = (vf - vi)/2 -20 = vf - 20 vf = 0 I leave the rest to you...

    1 Answers · Science & Mathematics · 29/08/2011

  2. Acceleration = (f/m) = 4,000/2,000) = 2m/sec^2. Maximum V = sqrt.(ar) = 20m/sec. (20 x 3.6) = 72kph., should you need that.

    1 Answers · Science & Mathematics · 02/02/2014

  3. (2m/s) / (9.81m/s^2) = 0.204s He will start to fall down after 0.204 seconds, this is the moment where he will be the highest. d=-(a/2)t^2+vt d is how much the center of mass is raised, a is acceleration, v is initial velocity, t is time d=-(9.81/2)t^2...

    1 Answers · Science & Mathematics · 07/12/2010

  4. (a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

    1 Answers · Science & Mathematics · 24/06/2016

  5. OK, simple V=D/T. Velocity = Distance/Time D = 2 x pi x r . T (in seconds) is 23.9 x 3600 (seconds in an hour) Since everything is nice an linear - the R for part be needs to be 1/3 of...

    1 Answers · Science & Mathematics · 04/07/2013

  6. that... doesn t seem to be a valid question. First, there s no units, so it s impossible to answer it for that reason alone. Second, if you want units of work, what you need is force and distance, not speed. W = FD And power is Work per unit time so...

    1 Answers · Science & Mathematics · 15/01/2009

  7. You need to use terminal velocity ideas. Check this link: http://en.wikipedia.org/wiki/Stokes%27_law Hope this helps. your_guide123@yahoo.com

    1 Answers · Science & Mathematics · 18/11/2012

  8. m1 v1 + m2 v2 = m1 u1 + m2 u2 m1 = 69 + 133 = 202 kg m2 = 15 kg v1 = v2 = 0 u2 - u1 = 4.4 m/s u2 = u1 + 4.4 m1 v1 + m2 v2 = m1 u1 + m2 u2 0 = 202 u1 + 15 (u1 + 4.4) 0 = 202 u1+ 15 u1 + 66 -66 = 217 u1 u1 = -66/217 = -0.304 m/s (it negative because the direction is opposed the package direction)

    1 Answers · Science & Mathematics · 14/03/2013

  9. a) 0.5*m*v^2 = 12 J b) F*d = 600 J c) F*d = -200J d) F*d = m*g*(8sin(37)) = -283.38 J e) F*d = 0 J f) W_net = 600 - 200 - 283.38 = 116.62 J

    1 Answers · Science & Mathematics · 29/11/2009

  10. (a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

    1 Answers · Science & Mathematics · 14/10/2013

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