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1. ### Why is divorce considered failure?

I do not consider divorce to be a failure, when compared with living in a marriage that isn't happy or fulfilling. Of the two, I'd say the marriage is the failure, and the divorce would be the better choice. I do take issue with your generalization that...

8 Answers · Family & Relationships · 21/08/2015

2. ### §☺☻Oscillations and Kinetic Energy... is for exam!!!?

... 1/2 its value or = 0.28125 J be called x. SPE = 0.28125 = 1/2kx² = (0.5)(20)x² = 10x² x² = 0.028125...

2 Answers · Science & Mathematics · 02/08/2015

3. ### Is this a good pokemon team? How could I make it better? (10 point?)?

.../Natural Cure EVs: 252 Atk, 252 Spe, 4 HP Nature: Timid - Hydro Pump - Ice...

1 Answers · Games & Recreation · 20/07/2015

4. ### Is my Latin correct?

...what I think you mean), Latin used the word for 'hope' - spes. For personal possession with forms of the verb 'to be,' ...

2 Answers · Society & Culture · 29/06/2015

5. ### Oscillating circle?

a) F_max = k*x_max = k*A b) KE_max = SPE_max = 1/2*k*x_max^2 = 1/2*k*A^2 c) Same as b) d) Use...

2 Answers · Science & Mathematics · 23/06/2015

6. ### have u ever asked in class *what is spe@m?*?

No. But once my moms brother was in third grade and asked the class for a bj even tho he had no clue what it was

2 Answers · Entertainment & Music · 26/05/2015

7. ### How far would a spring, with a spring constant of 350 N/m, have to be stretched beyond equilibrium to produce a velocity of 15 m/s when...?

KE = SPE 1/2*m*v_max^2 = 1/2*k*x^2 x = v*sqrt(m/k) x = 15 m/s * sqrt(0.800 kg / 350 N/m) = 0.72 m

1 Answers · Science & Mathematics · 21/05/2015

8. ### How far from equilibrium does a spring (spring constant 350 N/m) have to be pulled back in order for a 250 g object to have a velocity of...?

SPE = KE of object at equilibrium position of spring SPE = (0.5)(0.250)(5)² = 3.125 J 1/2kx² = 3.125 x² = 6.25/350 x = 0.1336 m ≈ 13.4 cm ANS

1 Answers · Science & Mathematics · 12/05/2015

9. ### What is the spring constant of this spring?

spring deformation = x = 25 - 22 = 3 cm = 0.03 m SPE = 125 = 1/2kx² = (0.5)k(0.03)² k = 250/(0.03)² = 277777.8 ≈ 280,000 N/m ANS

1 Answers · Science & Mathematics · 11/05/2015

10. ### PHYSICS HELP...BEST ANSWER AWARDED!?

...785 N x = 0.5 m k = F/x = 785/0.5 ≈ 1570 N/m ANS-1 SPE = 1/2kx² = (0.5)(1570)(0.5)² ≈ 196 J ANS-2 "...

1 Answers · Science & Mathematics · 11/05/2015