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Q = m * Cp * dT Heat = mass * Specific Heat * Temperature Change 1635J = 2000g * Cp * 3K Cp = 1635/(2000 * 3) 0.2725 J/(g*K) or 272.5 J/(kg*K)

1 Answers · Science & Mathematics · 28/09/2008

height=initial velocity times time --1/2gravity times time squared h=2t-4.905t^2 you need to find the time when the velocity is zero 0=v-at t=.204 seconds plug it back in to the first equation h=2(.204)-4.905(.204)^2 h=.204 meters

1 Answers · Science & Mathematics · 04/10/2011

g = - 10 (It's going down. vi = 20 m/s t = 1 second vf = ???? g = (vf - vi)/t -10 = (vf - 20)/1 -10 = vf - 20 10 = vf This means it is still going up and the speed is 10 m/s up -10 = (vf - vi)/2 -20 = vf - 20 vf = 0 I leave the rest to you...

1 Answers · Science & Mathematics · 29/08/2011

Momentum is conserved; the initial momentum of the system is zero, as is the final momentum: m*V = M*v → v = V*m/M = 4.1*15/188 v = 0.327 m/s

1 Answers · Science & Mathematics · 03/12/2012

Your picture did not open. I am trying to answer your questions as far as possible with the help of your word problem only. 1) Use energy conservation here. Net change in kinetic energy = 0.5 mv^2 [as final speed = 0] = 4.86 J This...

1 Answers · Science & Mathematics · 19/01/2014

that... doesn't seem to be a valid question. First, there's no units, so it's impossible to answer it for that reason alone. Second, if you want units of work, what you need is force and distance, not speed. W = FD And power is Work per unit time so...

1 Answers · Science & Mathematics · 15/01/2009

You need to use terminal velocity ideas. Check this link: http://en.wikipedia.org/wiki/Stokes%27_law Hope this helps. your_guide123@yahoo.com

1 Answers · Science & Mathematics · 18/11/2012

Acceleration = (f/m) = 4,000/2,000) = 2m/sec^2. Maximum V = sqrt.(ar) = 20m/sec. (20 x 3.6) = 72kph., should you need that.

1 Answers · Science & Mathematics · 02/02/2014

m1 v1 + m2 v2 = m1 u1 + m2 u2 m1 = 69 + 133 = 202 kg m2 = 15 kg v1 = v2 = 0 u2 - u1 = 4.4 m/s u2 = u1 + 4.4 m1 v1 + m2 v2 = m1 u1 + m2 u2 0 = 202 u1 + 15 (u1 + 4.4) 0 = 202 u1+ 15 u1 + 66 -66 = 217 u1 u1 = -66/217 = -0.304 m/s (it negative because the direction is opposed the package direction)

1 Answers · Science & Mathematics · 14/03/2013

a) 0.5*m*v^2 = 12 J b) F*d = 600 J c) F*d = -200J d) F*d = m*g*(8sin(37)) = -283.38 J e) F*d = 0 J f) W_net = 600 - 200 - 283.38 = 116.62 J

1 Answers · Science & Mathematics · 29/11/2009

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