Sort by

- Relevance
- |Time

a) F_max = k*x_max = k*A b) KE_max =

**SPE**_max = 1/2*k*x_max^2 = 1/2*k*A^2 c) Same as b) d) Use...2 Answers · Science & Mathematics · 23/06/2015

KE =

**SPE**1/2*m*v_max^2 = 1/2*k*x^2 x = v*sqrt(m/k) x = 15 m/s * sqrt(0.800 kg / 350 N/m) = 0.72 m1 Answers · Science & Mathematics · 21/05/2015

**SPE**= KE of object at equilibrium position of spring**SPE**= (0.5)(0.250)(5)² = 3.125 J 1/2kx² = 3.125 x² = 6.25/350 x = 0.1336 m ≈ 13.4 cm ANS1 Answers · Science & Mathematics · 12/05/2015

spring deformation = x = 25 - 22 = 3 cm = 0.03 m

**SPE**= 125 = 1/2kx² = (0.5)k(0.03)² k = 250/(0.03)² = 277777.8 ≈ 280,000 N/m ANS1 Answers · Science & Mathematics · 11/05/2015

...785 N x = 0.5 m k = F/x = 785/0.5 ≈ 1570 N/m ANS-1

**SPE**= 1/2kx² = (0.5)(1570)(0.5)² ≈ 196 J ANS-2 "...1 Answers · Science & Mathematics · 10/05/2015

...into the v equation v(0) = (2*pi/0.94s)*(0.10m)*cos(pi/5) d) Using x(0),

**SPE**= 1/2*k*x^2 e) Using v(0) and x(0), E = 1/2*m*v^2 + 1/2*k...1 Answers · Science & Mathematics · 27/04/2015

...wrong, ignore what I say below.) Calculate the spring potential energy

**SPE**= (1/2)*k*x^2 at both x = .248 and .131. Total energy will be conserved...1 Answers · Science & Mathematics · 17/04/2015

...1)(3)² = 4.5 J ANS a. max amplitude occurs when total

**SPE**= KE : 4.5 = 1/2kx² = (0.5)(10)x² x² = 4.5/5 = 0...1 Answers · Science & Mathematics · 25/03/2015

... Equivalence." http://en.wikipedia.org/wiki/Mass_in_

**spe**… http://en.wikipedia.org/wiki/Mass%E2%80%93energy_equivalence Scroll...3 Answers · Science & Mathematics · 19/04/2015

...d) EPE = 0 at max KE. (e) Given above. (f) (EPE or)

**SPE**= ½kx² = ½ * 298N/m * (0.0200m)² = 0...1 Answers · Science & Mathematics · 31/01/2015