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From your problem statement it sounds like you're only interested in the vertical dimension, and you also need to neglect the effect of aerodynamic drag. With these assumptions, right before the ball hits the ground it has converted...

2 Answers · Science & Mathematics · 15/07/2012

1 meter. .

2 Answers · Science & Mathematics · 18/12/2010

AN 83.....? (83 + 136) = 219kg. (15 x 4.4)/219 = 0.3m/sec., left.

2 Answers · Science & Mathematics · 05/10/2012

(a) translational kinetic energy = (1/2)*m*(v^2) =(1/2)*10*(10^2) =500J (b) rotational kinetic energy =(1/2)*I*(w^2) w-angular velocity(omega), I-moment of inertia =(1/2)*(2/5*m*r^2)(w^2...

2 Answers · Science & Mathematics · 25/12/2012

960mph. lol jk

2 Answers · Science & Mathematics · 10/08/2008

Don't forget to supply what units you are working with! (342 + 24.5) = apparent V of 366.5m/sec. a) (366.5/342) x 400 = 428.655Hz. b) 428.655Hz.

2 Answers · Science & Mathematics · 30/01/2013

(a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

1 Answers · Science & Mathematics · 24/06/2016

OK, simple V=D/T. Velocity = Distance/Time D = 2 x pi x r . T (in seconds) is 23.9 x 3600 (seconds in an hour) Since everything is nice an linear - the R for part be needs to be 1/3 of...

1 Answers · Science & Mathematics · 05/07/2013

(a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

1 Answers · Science & Mathematics · 14/10/2013

By I = ∆P = m∆v =>9.87 = 0.54 x ∆v =>∆v = 18.28 m/s

1 Answers · Science & Mathematics · 21/10/2013

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