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  1. From your problem statement it sounds like you're only interested in the vertical dimension, and you also need to neglect the effect of aerodynamic drag. With these assumptions, right before the ball hits the ground it has converted...

    2 Answers · Science & Mathematics · 15/07/2012

  2. AN 83.....? (83 + 136) = 219kg. (15 x 4.4)/219 = 0.3m/sec., left.

    2 Answers · Science & Mathematics · 05/10/2012

  3. (a) translational kinetic energy = (1/2)*m*(v^2) =(1/2)*10*(10^2) =500J (b) rotational kinetic energy =(1/2)*I*(w^2) w-angular velocity(omega), I-moment of inertia =(1/2)*(2/5*m*r^2)(w^2...

    2 Answers · Science & Mathematics · 25/12/2012

  4. Don't forget to supply what units you are working with! (342 + 24.5) = apparent V of 366.5m/sec. a) (366.5/342) x 400 = 428.655Hz. b) 428.655Hz.

    2 Answers · Science & Mathematics · 30/01/2013

  5. (a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

    1 Answers · Science & Mathematics · 24/06/2016

  6. OK, simple V=D/T. Velocity = Distance/Time D = 2 x pi x r . T (in seconds) is 23.9 x 3600 (seconds in an hour) Since everything is nice an linear - the R for part be needs to be 1/3 of...

    1 Answers · Science & Mathematics · 05/07/2013

  7. (a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

    1 Answers · Science & Mathematics · 14/10/2013

  8. By I = ∆P = m∆v =>9.87 = 0.54 x ∆v =>∆v = 18.28 m/s

    1 Answers · Science & Mathematics · 21/10/2013

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