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  1. we are going to work this out by using momentum mass of fisherman = 126kg mass of package=15m speed of boat =0m/s speed of package= 4.6m/s momentum before = momentum after (126 x 0) ( 15 x 4.6) = (126v) ( 15 x 0) [ the package will eventually come to rest afterwards] 69= 126v 69/126= v v=0.55m/s...

    2 Answers · Science & Mathematics · 02/05/2017

  2. ...any point = total energy = kinetic energy + spring potential energy KE = 1/2*m*v^2 SPE = 1/2*k*x^2 1) KE = 1/4*Total Energy TE = 1/4...

    1 Answers · Science & Mathematics · 22/04/2017

  3. ...25)m = -179 J The increase in spring potential energy is ΔSPE = ½kx² = ½ * 5.8N/m * (0.26m)² = 0.196...

    2 Answers · Science & Mathematics · 09/11/2016

  4. ...3000 N/m When stretched 0.21 m, two bands would have SPE = 1/2K(0.21)² = 1500(0.21)² = 66.15 ≈ 66 J ANS...

    1 Answers · Science & Mathematics · 03/08/2016

  5. ...mass then: The energy stored in spring when displacement = 30 cm is: SPE = 1/2kx² = (0.5)(200)(0.30)² = 9 J The KE of...

    1 Answers · Science & Mathematics · 25/07/2016

  6. ...energy. GPE = mgh = 0.143kg * 9.80m/s² * (7.15+14.7)m = 30.6 J SPE = ½kx² = ½ * 877N/m * (0.429m)² = 80...

    1 Answers · Science & Mathematics · 22/07/2016

  7. (a) p = mv = 1.2e5 kg·m/s (b) v = p / m = 1.2e5kg·m/s / 8kg = 1.5e4 m/s = 15 km/s

    1 Answers · Science & Mathematics · 24/06/2016

  8. ...left off units) The max spring pe occurs at the max displacement SPE Max = 1/2*k*A^2 = 1/2*m*w^2*A^2 All your...

    1 Answers · Science & Mathematics · 11/06/2016

  9. max SPE = 1/2kx² = (0.5)(600)(0.05)² = 0.75 J 0.75 = 1/2mV²...

    2 Answers · Science & Mathematics · 15/04/2016

  10. SPE = 1/2kx² {where x = extended length in cm - 20} W1 = SPE...SPE(20) = (k/2)[(30-20)² - (20-20)²] = k/2(100) = 50k W2 = SPE(40) - SPE(30) = (k/2)[(40-20)² - (30-20)²] = k/2(400 - 100...

    1 Answers · Science & Mathematics · 14/04/2016

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