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  1. ...inertia in kg•m² I = cMR²     M is mass (kg), R is radius (meters)     c = 1 for a ring or hollow cylinder     c = 2/5...

    1 Answers · Science & Mathematics · 18/05/2020

  2. 4. Li = m2 v R/ 4  m2*v*R/4 = (½*m1*R² + m2*(R/4)²...R/16)*w 4v = (8R+R)*w = 9Rw w = 4v / 9R for v=6 R=12 w = 4*6 / 9*12 = 2/9 = 0.22 rad/s

    1 Answers · Science & Mathematics · 13/05/2020

  3. ...after engine shutoff, KE + GPE = constant ½mv² - GmM/R = k and if we divide through by the rocket's mass m we get v²/2 - GM...

    1 Answers · Science & Mathematics · 12/05/2020

  4. ... middle school we learn Newton's model.  W = mGM/R^2 where you, for example, are the mass m and M is Earth...

    5 Answers · Science & Mathematics · 10/05/2020

  5. ...force) is equal to the centripetal force: GmM / R² = mv²/R rock mass m cancels, and so M = v²R / G M = (12m...

    1 Answers · Science & Mathematics · 07/05/2020

  6. ... R1 = 2R2 = 4R3 = 8R4 Let R4 = RΩ =>R1 = 8R Ω =>R2 = 4R Ω...

    3 Answers · Science & Mathematics · 01/06/2020

  7. m*V^2/r-m*g = 6  m(V^2/5-g) = 6 m = 6/(V^2/5-g)  ...where the quantity V^2/5-g must be positive (V^2/5 > g) 

    1 Answers · Science & Mathematics · 06/05/2020

  8. ...in this situation, so we just need to find the centripetal force: F = mv²/r = 9.11*10^-31 * (2.29*10^6)² / (5.23*10^-11) . .= 9.13*10^-8 N (b...

    2 Answers · Science & Mathematics · 06/05/2020

  9. ...*2.00m*cos36.8º + 360N*(5.00m - 1.50m*cos53.13º) - R*5.00m where R is the vertical force under the right leg R = 449...

    1 Answers · Science & Mathematics · 14/05/2020

  10. ...0.06m - 0.60N·m) / 0.00342kg·m² so the linear acceleration a = α*r = α * 0.06m a = ([4.0kg*(9.8m/s² - a) - M*(9.8m/s² + a)]*0...

    3 Answers · Science & Mathematics · 01/05/2020

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