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1. E = I*

**R**. If the resistance is cut in half, and the current remains the...1 Answers · Science & Mathematics · 26/02/2019

We want the displacement current's magnetic field at

**r**to be the same magnitude as the wire's magnetic field at**r**, but in the opposite direction...1 Answers · Science & Mathematics · 02/05/2019

The required centripetal force is F = mv^2 /

**r**And it acts towards the centre of the circle NOT along...2 Answers · Science & Mathematics · 01/07/2019

P * V = n *

**R*** T The unit of pressure is N/m^2. The unit of...1 Answers · Science & Mathematics · 23/05/2019

we must use

**r**^2 v= constant.**r**is the radius and v is the velocity. first condition...4*4=1. This remains a constant. In the second segment**r**=1. velocity =1 m/s. In the third segment (1/4)^2 v=1. v=16 m/s...3 Answers · Science & Mathematics · 15/09/2019

V = kq/

**r**so**r**= kq/V = 8.98755179e9 * 1e-5/1e4 = 8.98755179e9 * 1e-5/1e4 = = 8.98755179e9...3 Answers · Science & Mathematics · 15/09/2019

V/I =

**R****R**= 6 / 8 = 0.75 Ohm Now when spinning the net emf...3 Answers · Science & Mathematics · 05/01/2019

(B) mv^2/

**r**= m*6.45*g = (73.0 kg)(9.81 m/s^2)(6.45) = Around 4500 N but use a calculator. (A) v^2/**r**<= 6.45*g =>**r**>= v^2/(6.45*g) = (103 m/s)^2/(6.45*9.81 m/s^2) = around 15m but use a calculator.1 Answers · Science & Mathematics · 12/12/2019

Diagram: q1. .A. . . B VA = kq/

**r**= 8.99*10^9 * 6.25*10^-8 / 0.150 VB = kq/**r**= 8.99*10^9 * 6.25*10^-8 / 0...3 Answers · Science & Mathematics · 23/05/2019

...39;s call it α. Then the linear acceleration of the mass is a = α*

**r**= α * 0.119m and the distance the mass travels between the two times...3 Answers · Science & Mathematics · 08/07/2019