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  1. potential = kQ / r where k = 1/4πε₀ = 8.99e9N·m²/C² so potential = 8.... ◄ then 11.7 V = 8.99e9N·m²/C² * 57.7e-12C / r solves to r = 0.0443 m = 44.3 mm ◄ If you find this helpful, please...

    1 Answers · Science & Mathematics · 03/02/2020

  2. (B) mv^2/r = m*6.45*g = (73.0 kg)(9.81 m/s^2)(6.45) = Around 4500 N but use a calculator. (A) v^2/r <= 6.45*g => r >= v^2/(6.45*g) = (103 m/s)^2/(6.45*9.81 m/s^2) = around 15m but use a calculator.

    1 Answers · Science & Mathematics · 12/12/2019

  3. Diagram: q1. .A. . . B VA = kq/r = 8.99*10^9 * 6.25*10^-8 / 0.150 VB = kq/r = 8.99*10^9 * 6.25*10^-8 / 0...

    3 Answers · Science & Mathematics · 23/05/2019

  4. ...39;s call it α. Then the linear acceleration of the mass is a = α*r = α * 0.119m and the distance the mass travels between the two times...

    3 Answers · Science & Mathematics · 08/07/2019

  5. 2 R above the surface is 3 R from the center. So the acceleration of gravity is 1/9 of the surface value. Then force = mass * acceleration = 1950 * (9.80665 / 9) = 2124 newtons.

    1 Answers · Science & Mathematics · 29/10/2019

  6. Using Gauss’ law with a coaxial cylindrical surface at r and length L we have E(r) 2πr L =  ρ πR^2 L...

    1 Answers · Science & Mathematics · 23/02/2020

  7. The volume of a sphere is 4/3 pi() r^3 and the volume of a cube is L^3 so to transform a sphere into a cube...

    7 Answers · Science & Mathematics · 01/05/2019

  8. Energy E = R*I^2*t = 1.5*3^2*3.5 = 47.25 joule = 11.3 cal

    3 Answers · Science & Mathematics · 03/03/2020

  9. (sin i) / (sin r) = (RI of Y) / (RI of X) = 1.24 / 1 = 1.24 sin r = (sin i) / 1.24 = (sin 14°) / 1.24 = 0.244 / 1.24 = 0.197 r = arcsin 0.107 = 11.36° (ans)

    1 Answers · Science & Mathematics · 19/11/2019

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