4. Li = m2 v

**R**/ 4 m2*v***R**/4 = (½*m1*R² + m2*(**R**/4)²...**R**/16)*w 4v = (8R+**R**)*w = 9Rw w = 4v / 9R for v=6**R**=12 w = 4*6 / 9*12 = 2/9 = 0.22 rad/s1 Answers · Science & Mathematics · 13/05/2020

m*V^2/

**r**-m*g = 6 m(V^2/5-g) = 6 m = 6/(V^2/5-g) ...where the quantity V^2/5-g must be positive (V^2/5 > g)1 Answers · Science & Mathematics · 06/05/2020

...5(-4.12) Hence, F = 10.3 Newtons Now, F = μ

**R**so, 10.3 = μ(2.5 x 9.8) => 24.5μ Therefore, μ = 10.3/24.5 =>...2 Answers · Science & Mathematics · 24/05/2020

... middle school we learn Newton's model. W = mGM/

**R**^2 where you, for example, are the mass m and M is Earth...5 Answers · Science & Mathematics · 10/05/2020

...after engine shutoff, KE + GPE = constant ½mv² - GmM/

**R**= k and if we divide through by the rocket's mass m we get v²/2 - GM...1 Answers · Science & Mathematics · 12/05/2020

...current-carrying wire is B = µ₀*I / 2π

**r**where µ₀ = 4πe-7 T·m·s/C so B = µ...1 Answers · Science & Mathematics · 21/05/2020

...*2.00m*cos36.8º + 360N*(5.00m - 1.50m*cos53.13º) -

**R***5.00m where**R**is the vertical force under the right leg**R**= 449...1 Answers · Science & Mathematics · 14/05/2020

...in this situation, so we just need to find the centripetal force: F = mv²/

**r**= 9.11*10^-31 * (2.29*10^6)² / (5.23*10^-11) . .= 9.13*10^-8 N (b...2 Answers · Science & Mathematics · 06/05/2020

...0.06m - 0.60N·m) / 0.00342kg·m² so the linear acceleration a = α*

**r**= α * 0.06m a = ([4.0kg*(9.8m/s² - a) - M*(9.8m/s² + a)]*0...3 Answers · Science & Mathematics · 01/05/2020

a) angular velocity = d/dt(theta) = 2t + 6 t’2 = 2+6 = 8 rad/sec. b) angular acceleration = 2 + 12 t = 14 rad/ sec’2. c) at

**r**=0.5 m, angular acceleration = 14 rad/sec’2 and tangential acceleration a =**r**xalpha = 0.5 x14 = 7 m/sec’2.1 Answers · Science & Mathematics · 22/05/2020

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