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1. ### Calculate r sub u X r sub v and || r sub u X r sub v|| for both of the following parametrizations:?

a) r _u = <1, 0, f_u> r _v = <0, 1, f_v>. So, r _u x r _v |i...b) r _u = <- R sin u sin v, 0, 0> r _v = < R cos u cos v, 0, - R sin v>...

1 Answers · Science & Mathematics · 28/05/2015

2. ### 1+ r + r ^2+ r ^3+ ... + r ^n=[1- r ^(n+1)]/(1- r )?

1 + r + r ^2 + r ^3 + ... + r ^n = [1 - r ^(n + 1)] / (1 - r ), for n >= 0. What we want to do ...be LHS = 1... 1 = 1, and RHS = [1 - r ^(0 + 1)] / (1 - r ) = [1 - r ] / [1 - r ] = 1 So the formula holds true for...

4 Answers · Science & Mathematics · 13/02/2007

3. ### MATH!!! Make r the subject of the formula.?

r - 3 = pi(t - 2r) r - 3 = pi(t) - 2pi( r ) r + 2pi( r ) = pi(t) + 3 r (1 + 2pi) = pi(t) + 3 r = (pi(t) + 3)/(1 + 2pi) i am khayyam

5 Answers · Science & Mathematics · 07/03/2010

4. ### Solve for A1/A2 in terms of R (logs)?

R = 2.3log(A1 + 3000) - 5.1 gives ( R +5.1) = 2.3log(A1 + 3000) log(A1 + 3000) = ( R +5.1)/2.3 (A1 + 3000) = 10^[( R +5.1)/2.3] A1 = 10^[( R ...

1 Answers · Science & Mathematics · 02/05/2011

5. ### Let R be a finite ring with unity?

If R is the zero ring, a=0 and is a zero-divisor. Assume | R ...;> 0} . If 1 is in S, then ar=1 for some r , and a is a unit. If 1 is not in S, then ar = as for...

1 Answers · Science & Mathematics · 12/04/2015

6. ### Find r if 5Pr = 2 6Pr-1?

5Pr = 5!/(5- r )!, and 2(6P( r -1)) = 2*6!/(6- r +1)! so 5!(6- r +1)! = 2*6!(5- r )! 6*5!(7- r )! = 6*2*6!(5- r )! 6!(7- r )! = 12*6!(5- r )! 12 = 6!(7- r )! / 6!(5- r )! 12 = (7- r )(6- r ) so the ...

3 Answers · Science & Mathematics · 13/11/2012

7. ### Write and expression for r and s?

( r - s)(x) = r (x) - s(x) = x - 4 - 3x² ( r s)(x) = r (x) s(x) = x - 4 3x² ( rs )(-2) = r (-2) * s(-2) = (-2 - 4)(3(-2)²) = (-6)(3 * 4) = -6 * 12 = -72 I hope this helps!

2 Answers · Science & Mathematics · 16/12/2016

8. ### Show that C(n+1, r +1) = ∑ (from k= r to n) C(k, r )?

First , prove C(n, r ) = C(n-1, r ) + C(n-1, r -1) . Assume there are n ... not included in chosen numbers then C(n-1, r ) ways exist because we must choose r numbers out of 2～n . If...

1 Answers · Science & Mathematics · 26/10/2017

9. ### How do I solve for r ?

(1 + r √(s - 6)) / ( r + √(s - 6)) = z (1 + r √(s - 6)) = z( r + √(s - 6)) 1 + r √(s - 6) = rz + z√(s - 6) r √(s - 6) - rz = z√(s - 6) - 1 r (√(s - 6) - z) = z√(s - 6) - 1 r = (z√(s - 6) - 1) / (√(s - 6) - z) ♣♦

1 Answers · Education & Reference · 30/08/2011

10. ### What's r is r ^16 = 32?

r ^16 = 32 r ^16 = 2^5 log r ^16 = log 2^5 16 log r = 5 log 2 log r = 5/16 log 2 log r = log 2^5/16 log r = log 32^1/16 r = 32^1/16

5 Answers · Science & Mathematics · 02/03/2010