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Well, it is somewhere between

**R**and L, with speakers varying between...not individual letters. So you can't write**R**along, but you can write syllables that start with**R**...8 Answers · Society & Culture · 27/05/2008

Let

**r**= (x(1), x(2), ..., x(n)). So, |**r**...x(2))^2 + ... + (x(n))^2]. Hence,**r**(hat) = (x(1)/√[(x(1))^2 + (x(2))^2...x(1))^2 + ... + (x(n))^2)^(-1/2) = (n-1)/|**r**|. In the case where n = 3, this ...1 Answers · Science & Mathematics · 13/03/2013

this can be written as

**r**^2 + 3r - 2 = 0 Now to solve this you can use the discriminat method (delta = b^2...the method of completing the square.**r**^2 + 3r + (3/2)^2 - (3.2)^2 -2 =0 (**r**+ 3/2)^2 = 9/4 + 2 = 17/4**r**+3/2 = +or- sqrt(17/4)**r**= + sqrt(17/4) - 3/2 or...3 Answers · Science & Mathematics · 15/09/2010

(

**r**− 3)(**r**+ 9)=-9 =>**r**(**r**+ 9) −3(**r**+ 9)= -9 =>**r**^2 + 9r −3r − 27 = -9 =>**r**^2 + 6r − 18 = 0 now...4 Answers · Science & Mathematics · 15/12/2013

y =

**r***sin(T) We know that**r**= 5*sin(T) which gives sin(T) =**r**/5 And**r**^2 = x^2...3 Answers · Science & Mathematics · 03/05/2010

**r**^2 - 5r - 6r + 30 = 0**r**(**r**- 5) - 6(**r**- 5) = 0 (**r**- 6)(**r**- 5) = 0**r**- 6 = 0 or**r**- 5 = 0**r**= 6 or**r**= 53 Answers · Science & Mathematics · 06/02/2011

The DVD-

**R**format was developed by Pioneer in the autumn of 1997. ... system of tracking and speed control used by DVD+**R**being less susceptible to interference and error than the LPP system used...3 Answers · Computers & Internet · 02/10/2007

Since

**r**^2 = (-**r**)^2, we can assume without loss of generality that**r**≥ 0. For each fixed**r**≥ 0, A(**r**) is a circle centered at (0, 0) with radius**r**. (When**r**= 0, then A(0) is simply {(0, 0)}.) Hence...1 Answers · Science & Mathematics · 27/03/2012

**R**=3a^2b Since b is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. 3a^2b=**R**Divide each term in the equation by 3a^(2). 3a^2b/3a^2=**R**/3a^2...2 Answers · Education & Reference · 16/07/2013

1)

**r**= 4∙sin(θ)**r**= 0 for 4∙sin(θ) = 0 sin(θ) = 0 θ = 0 or θ = π**r**' = 4∙cos(θ)**r**' = 0 for 4∙cos(θ) = 0 cos...or θ = π 3 + 2∙cos(0) = 5 3 + 2∙cos(π) = -5 so**r**-max at θ = 0 Graph: http://i48.tinypic.com/doauci...1 Answers · Science & Mathematics · 22/05/2012