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1. ### A wire of length L1 and diameter d1 has resistance R1. A second wire of the same material has length.......?

Recall: R = ρ * (ℓ/S) First wire r₁ = ρ * (ℓ₁/...

1 Answers · Science & Mathematics · 23/03/2021

2. ### this physics question stumped me?

F = k q1 * q2 / r ^2; (Coulomb's force. Centripetal force). F = m v^2...2 * 10^-19 ) * (1.6 * 10^-19 ) / (5.9 * 10^-12)^2 = 1,324* 10^-5 N. m v^2 / r = 1,324* 10^-5, v = radicequadrata( 1,324* 10^-5 * r / m); v = radicequadrata(1,324* 10...

2 Answers · Science & Mathematics · 01/04/2021

3. ### A 19.0 Ω, 11.0 Ω, and 6.00 Ω resistor are connected in parallel to an emf source. A current of 4.00 A is in the 11.0 Ω resistor.?

1/ R = 1/19 + 1/11 + 1/6 1/ R = 0.0526 + 0.0909 + 0.1667 1/ R = 0.3102 R = 3.22 Ω E = IR = 4•11 = 44 volts I = E/ R = 44/19 I = E/ R = 44/6

2 Answers · Science & Mathematics · 14/04/2021

4. ### What is the total resistance of the circuit below?

1/ R = 1/2 + 1/3 + 1/1 1/ R = 0.5 + 0.333 + 1 = 1.833 R = 1/1.833 = 0.545 Ω or 1/ R = 3/6 + 2/6 + 6/6 = 11/6 R = 6/11 = 0.545  Ω

3 Answers · Science & Mathematics · 01/04/2021

5. ### Suppose you arrive at a planet with the same mass per unit volume as the Earth but has 31 times Earth's radius. ?

ge = ρ* r ^3/ r ^2 = ρ* r gp = ρ*31^3* r ^3/(31^2* r ^2) = ρ*31* r gp/ge = ρ*31* r / (ρ* r ) = 31  gravity on planet gp = 31 times gravity ge on Earth

2 Answers · Science & Mathematics · 07/04/2021

6. ### Circuit problem ?

If = V/ R = 12/9 = 4/3 of Amps  timeconstant Ƭ = L/ R = 1.2/9 = 0.1333 sec  0.5 = 1-e^-k e^k = 0.5 k*ln e = ln 0.5.....(ln e = 1) k = -0.693 = -t/Ƭ  t = 0.693*0.1333 = 0.092 sec

2 Answers · Science & Mathematics · 15/04/2021

7. ### I need help someone. Physics?

... of each of your resistors. Then simply calculate resistance R = ρL/A ... where ρ is the given resistivity. L should...

2 Answers · Science & Mathematics · 28/03/2021

8. ### How do I compute this problem? I solved it but ended up with all weird fractional values.?

(b) m*ω^2* r *μ = m*g mass m cancels  ω = √g/( r *μ) = √4g/ r = √4*9.806/7 = 2.367...22.6 rpm  (c) time period T = 1/f = 1/0.377 = 2.65 sec radial acc. ra = ω^2* r = 2.367^2*7 = 39.2 m/sec^2 ( ≅ 4g) tangential acceleration ta = 0  people feel ...

2 Answers · Science & Mathematics · 28/03/2021

9. ### Does anyone know how to do this physics?

(a) ω = v/ r = 0.45m/s / 0.05m = 9 rad/s (b) KE = ½Iω² = ½ * 2.2E-3kg·m² * (9rad/s)² = 0.089 J (c) L = Iω = 2.2E-3kg·m² * 9rad/s = 0.020 kg·m²/s

1 Answers · Science & Mathematics · 22/03/2021

10. ### Physics Question?

MoI J = m* r ^2 = 22*0.36^2 = 2.85 kg*m^2 ang. acc. α = T/J = 5.7/2.85 = 2.00 rad/sec^2

1 Answers · Science & Mathematics · 06/04/2021

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