**R**= 1.1926, -4.1926 Try using MathWay.com Hope this helps!4 Answe

**r**s · Science & Mathematics · 07/04/2013**r**= ± 3 - √3, ± 1 - √3 so**r**IS i**r****r**ational the**r**efo**r**e it must be i**r****r**ational s = ±√[**r**^2 + (√3)**r**.... Solve the**r**esulting qua**r**tic equation:**r**^4 - 4**r**^2s^2 - 6**r**^2 + 4s^4 - 12s^2 + 9 = 0 fo**r**eithe**r**"**r**" o**r**...1 Answe

**r**s · Science & Mathematics · 24/01/2010Easy! :) Add "

**r**" from the right side to the left, and you will get 10r (pretend there is an... 10r). Then you will get 10r = 20. Divide each side by 10, and**r**= 2.7 Answe

**r**s · Science & Mathematics · 10/10/2011Complete the square

**r**^2 + 3r = 2 (**r**+ 3/2)^2 - 9/4 = 2 (**r**+ 3/2)^2 = 2 + 9/4 (**r**+ 3/2)^2 = 17/4**r**+ 3/2 = +/- Sqrt 17/4**r**= - 3/2 +/- Sqrt 17/4 If you need to go further**r**= - 3/2 + 2.0615 = 0.5615**r**= - 3/2 - 2.0615 = - 3.56151 Answe

**r**s · Science & Mathematics · 16/08/20105Pr = 5!/(5-

**r**)!, and 2(6P(**r**-1)) = 2*6!/(6-**r**+1)! so 5!(6-**r**+1)! = 2*6!(5-**r**)! 6*5!(7-**r**)! = 6*2*6!(5-**r**)! 6!(7-**r**)! = 12*6!(5-**r**)! 12 = 6!(7-**r**)! / 6!(5-**r**)! 12 = (7-**r**)(6-**r**) so the ...3 Answe

**r**s · Science & Mathematics · 13/11/2012(

**r**^2 - 4r - 5)/[5(**r**-5)] = (**r**-5)(**r**+1)/5(**r**-5) simplify by**r**-5: (**r**+1)/5 that's your result :) if you're not sure how to find roots of**r**^2 - 4r - 5, here's how you do it. 1. Find the delta (...5 Answe

**r**s · Science & Mathematics · 07/10/2011I = e/

**R**+**r**IR = e + rR {multiply both sides by**R**} IR - rR = e {subtract rR from both sides} (I -**r**)**R**= e {factor left side}**R**= e/(I -**r**) {divide both sidea by (I -**r**)4 Answe

**r**s · Science & Mathematics · 13/10/2007**r**- 2s = 14 Solve for s: Subtract**r**off both sides: -2s = 14 -**r**Multiply both sides by -1 to avoid trouble later: 2s =**r**- 14 Divide by 2: s = (**r**- 14)/25 Answe

**r**s · Science & Mathematics · 21/09/2012this can be written as

**r**^2 + 3r - 2 = 0 Now to solve this you can use the discriminat method (delta = b^2...the method of completing the square.**r**^2 + 3r + (3/2)^2 - (3.2)^2 -2 =0 (**r**+ 3/2)^2 = 9/4 + 2 = 17/4**r**+3/2 = +or- sqrt(17/4)**r**= + sqrt(17/4) - 3/2 or...3 Answe

**r**s · Science & Mathematics · 15/09/2010**r**= c / (2π) c = 2 π**r**c is ci**r**cumfe**r**ence and**r**is**r**adius of a ci**r**cle.2 Answe

**r**s · Science & Mathematics · 08/12/2007