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a. R = ρL/A = 1.72e-8Ω·m * 3.00m / π(0.000250m)² = 0.263 Ω b. p.d. = I* R = 0.400A * 0.263Ω = 0.105 V c. field E = p.d. / ...

total R = E/I = 7.5/0.1 = 75 Ω R = 75 – 10 – 15 = 50 Ω

... necessary, convert it to radians per second. A) v = ω * r = ω * 1m B) a_c = ω² * r = ω² * 1m C) F_c...

... kinetic energy KEr = (J/2)*ω^2 moment of inertia J = 2/5*m* r ^2 (it has a mass distributed homogeneously) ω^2 = V^2/ r ^2...

...there is friction sufficient to keep the angular velocity of the ball such that ω = v/ r For a solid sphere, I = (2/5)mR² and rotational KE...

...and you want to know the velocity of an object 4 m from the center of rotation. v = ω r v = 2π(4) = 8π m/s ≈ 25 m/s◄ 

drop on diode = 0.5 V I1 = 24/(56*2) = 0.214 A I2 = 24/56 = 0.428 A  I3 = (24-0.5)/56 = 0.420 A  Ib = I1+I2+I3 = 1.06 A (1.1 with jut 2 sign. figures) 

Call the starting height h.  At the top of the track, the block's speed is momentarily zero. Thus mgh = mg(2R)  --> h = 2R At the end of the track the block has total energy of E = 1/2mv^2 +mgR  and by conservation of energy E...