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  1. ... the pulley is tangential force Ft acting on pulley radius R T = Ft R Moment of inertia for disc of mass...

    2 Answers · Science & Mathematics · 27/11/2020

  2. ... to keep the cart on a circular path is F = mv²/ R = 475(20.0²)/25.0 = 7600 N This may be the answer you ...

    1 Answers · Science & Mathematics · 23/11/2020

  3. ...mu is coefficient of friction Centrifugal force Fcf = m v^2 / r Ffr = Fcf mu m g = m v^2 / r m cancels mu = v^2 / ( r g...

    1 Answers · Science & Mathematics · 18/11/2020

  4. a)a=  v^2 / r = 400/2 = 200 m/s^2 b) F = ma = 10 * 200 = 2000N  ( approximately 200kg weight equivalent assuming no mass is in the chain )

    2 Answers · Science & Mathematics · 18/11/2020

  5. ...convention, the gravitational PE at the surface is GPE₁ = -GmM / r GPE₁ = -6.674e−11N·m²/kg² * 1.60e3kg * 7.25e22kg / 1.7e6m...

    1 Answers · Science & Mathematics · 17/11/2020

  6. For the normal force to be zero, the centripetal acceleration must equal gravity (mass irrelevant): v²/ r = g v = √(gr) = √(9.8m/s² * 60m) = 24 m/s

    2 Answers · Science & Mathematics · 17/11/2020

  7. Centripetal force must equal weight mV²/ r = mg V² = rg = 0.98•9.8 V = 3.05 m/s Centripetal force...

    1 Answers · Science & Mathematics · 17/11/2020

  8. ...4.5)π)² + (2.2)(9.8) = 129 NCentripetal force f = mV²/ r = mrω²   ω is angular velocity in radians/sec...

    1 Answers · Science & Mathematics · 17/11/2020

  9. ... (centripetal, or radial) acceleration has direction toward the center of the m-g- r ; this direction also changes with the motion. The magnitudes...

    2 Answers · Science & Mathematics · 08/11/2020

  10. period T = 2*60 = 120 sec  centripetal acceleration ac : ac = ω ^2* r = (2PI)^2/T^2*6564/2 = 39.5/(1.44*10^4)*3.282*10^3 = 9.00 m/sec^2

    1 Answers · Science & Mathematics · 08/11/2020

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