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... the pulley is tangential force Ft acting on pulley radius

**R**T = Ft**R**Moment of inertia for disc of mass...2 Answe

**r**s · Science & Mathematics · 27/11/2020... to keep the ca

**r**t on a ci**r**cula**r**path is F = mv²/ R = 475(20.0²)/25.0 = 7600 N This may be the answe**r**you ...1 Answe

**r**s · Science & Mathematics · 23/11/2020...mu is coefficient of friction Centrifugal force Fcf = m v^2 /

**r**Ffr = Fcf mu m g = m v^2 /**r**m cancels mu = v^2 / (**r**g...1 Answe

**r**s · Science & Mathematics · 18/11/2020a)a= v^2 /

**r**= 400/2 = 200 m/s^2 b) F = ma = 10 * 200 = 2000N ( app**r**oximately 200kg weight equivalent assuming no mass is in the chain )2 Answe

**r**s · Science & Mathematics · 18/11/2020...convention, the g

**r**avitational PE at the su**r**face is GPE₁ = -GmM /**r**GPE₁ = -6.674e−11N·m²/kg² * 1.60e3kg * 7.25e22kg / 1.7e6m...1 Answe

**r**s · Science & Mathematics · 17/11/2020Fo

**r**the no**r**mal fo**r**ce to be ze**r**o, the cent**r**ipetal accele**r**ation must equal g**r**avity (mass i**r****r**elevant): v²/**r**= g v = √(g**r**) = √(9.8m/s² * 60m) = 24 m/s2 Answe

**r**s · Science & Mathematics · 17/11/2020Cent

**r**ipetal fo**r**ce must equal weight mV²/**r**= mg V² =**r**g = 0.98•9.8 V = 3.05 m/s Cent**r**ipetal fo**r**ce...1 Answe

**r**s · Science & Mathematics · 17/11/2020...4.5)π)² + (2.2)(9.8) = 129 NCent

**r**ipetal fo**r**ce f = mV²/**r**= m**r**ω² ω is angula**r**velocity in**r**adians/sec...1 Answe

**r**s · Science & Mathematics · 17/11/2020... (centripetal, or radial) acceleration has direction toward the center of the m-g-

**r**; this direction also changes with the motion. The magnitudes...2 Answe

**r**s · Science & Mathematics · 08/11/2020pe

**r**iod T = 2*60 = 120 sec cent**r**ipetal accele**r**ation ac : ac = ω ^2***r**= (2PI)^2/T^2*6564/2 = 39.5/(1.44*10^4)*3.282*10^3 = 9.00 m/sec^21 Answe

**r**s · Science & Mathematics · 08/11/2020

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