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  1. For a particle, angular momentum = m*v*r which is conserved since no external torques are ...

    1 Answers · Science & Mathematics · 29/02/2020

  2. E = R * (1/n² - 1/7²) where R is the Rydberg constant...

    1 Answers · Science & Mathematics · 27/04/2020

  3. The required centripetal force is F = mv^2 / r And it acts towards the centre of the circle NOT along...

    2 Answers · Science & Mathematics · 01/07/2019

  4. we must use r^2 v= constant. r is the radius and v is the velocity. first condition...4*4=1. This remains a constant. In the second segment r=1. velocity =1 m/s. In the third segment (1/4)^2 v=1. v=16 m/s...

    3 Answers · Science & Mathematics · 15/09/2019

  5. V = kq/r so r = kq/V = 8.98755179e9 * 1e-5/1e4 = 8.98755179e9 * 1e-5/1e4 = = 8.98755179e9...

    3 Answers · Science & Mathematics · 15/09/2019

  6. potential = kQ / r where k = 1/4πε₀ = 8.99e9N·m²/C² so potential = 8.... ◄ then 11.7 V = 8.99e9N·m²/C² * 57.7e-12C / r solves to r = 0.0443 m = 44.3 mm ◄ If you find this helpful, please...

    1 Answers · Science & Mathematics · 03/02/2020

  7. (B) mv^2/r = m*6.45*g = (73.0 kg)(9.81 m/s^2)(6.45) = Around 4500 N but use a calculator. (A) v^2/r <= 6.45*g => r >= v^2/(6.45*g) = (103 m/s)^2/(6.45*9.81 m/s^2) = around 15m but use a calculator.

    1 Answers · Science & Mathematics · 12/12/2019

  8. ...39;s call it α. Then the linear acceleration of the mass is a = α*r = α * 0.119m and the distance the mass travels between the two times...

    3 Answers · Science & Mathematics · 08/07/2019

  9. 2 R above the surface is 3 R from the center. So the acceleration of gravity is 1/9 of the surface value. Then force = mass * acceleration = 1950 * (9.80665 / 9) = 2124 newtons.

    1 Answers · Science & Mathematics · 29/10/2019

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