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1. ### left Ideal and ideal of ring R?

1) Let L = {r in R| ra = 0}. a) If u and v are in L then (u+v)a...b) If r is in R and u is in L then (ru)a = r(ua) = 0, so ru is in L, which shows that L is...

1 Answers · Science & Mathematics · 22/12/2010

2. ### let R be a relation defined by integers by aRb if a+b is congruent to 0(mod 3). show R is not an equivalence r?

R is not reflexive. For example, 1 is an integer, but it is not the case that 1 R 1, because 1 + 1 = 2 is not congruent to 0 mod 3. (So...R c, then a R c. Which shows that R is not transitive.)

1 Answers · Science & Mathematics · 09/03/2014

3. ### what does -(r+3)>9 equal?

-(r + 3) > 9 -(r) > 12 r < -12

5 Answers · Science & Mathematics · 24/11/2010

4. ### What is the minimum value of q(r)....?

Given: q(r) = r^3+7r^2-24r+6 To find maximum/minimum, take the derivative: q'(r) = 3r^2 + 14r - 24 Find the roots: 0 = 3r^2 + 14r - 24 r = (-14 +/- sqrt(14^2 - 4*3*(-24))) / (2*3) r = (-14 +/- sqrt(196 + 288)) / 6 r = (-14...

1 Answers · Science & Mathematics · 15/07/2008

5. ### How do you antidifferentiate e^(r/4)?

∫9re^(r/4) If we make the substitution u = e^(r/4), we get du = 4e^(r/4), or du/4 = e^(r/4), which we can write as: 9/4...u(ln(u) - 1) Replacing the u's with e^r/4: e^(r/4) * (ln(e^(r/4)) - 1), which is...

1 Answers · Science & Mathematics · 14/03/2011

6. ### solve A= 2 pi r^2 "plus" 2 pi r h for positive r

A = 2pi r^2 + 2pi(r)(h) First, move the A to the right hand side. That means one side will be zero. 2pi r^2 + 2pi(r)(h) - A = 0 This is in the form of a quadratic, as...

2 Answers · Science & Mathematics · 20/08/2008

7. ### VB : R = A + Csquared?

R=A + C^2 R-A= C^2 + or - sqrt(R-A) =C C=sqrt(R-A) or C=-sqrt(R-A)

2 Answers · Science & Mathematics · 30/08/2007

8. ### Derivative of r= 2∂ √cos∂?

r' = dr/d∂ = ∂ sqrt(cos∂) - (2∂ sin∂) / 2sqrt(cos∂) = = (2∂ cos∂ - 2∂ sin...

3 Answers · Science & Mathematics · 13/10/2008

9. ### Express (7r+10)/r(r+1)(r+2) in partial fractions?

(7r + 10)/r(r + 1)(r + 2) = A/r + B/(r + 1) + C/(r + 2) A(r + 1...(r + 1) = 7r + 10 r = 0 --> 2A = 10 --> A = 5 r = -1 --> -B = 3 --> B = -3 r = -2 --> 2C = -4...

1 Answers · Science & Mathematics · 03/01/2013

10. ### Algebra, solving for r?

r^2 - 5r - 6r + 30 = 0 r(r - 5) - 6(r - 5) = 0 (r - 6)(r - 5) = 0 r - 6 = 0 or r - 5 = 0 r = 6 or r = 5

3 Answers · Science & Mathematics · 06/02/2011