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    related to: R
  1. Well, it is somewhere between R and L, with speakers varying between...not individual letters. So you can't write R along, but you can write syllables that start with R ...

    8 Answers · Society & Culture · 27/05/2008

  2. Let r = (x(1), x(2), ..., x(n)). So, | r ...x(2))^2 + ... + (x(n))^2]. Hence, r (hat) = (x(1)/√[(x(1))^2 + (x(2))^2...x(1))^2 + ... + (x(n))^2)^(-1/2) = (n-1)/| r |. In the case where n = 3, this ...

    1 Answers · Science & Mathematics · 13/03/2013

  3. this can be written as r ^2 + 3r - 2 = 0 Now to solve this you can use the discriminat method (delta = b^2...the method of completing the square. r ^2 + 3r + (3/2)^2 - (3.2)^2 -2 =0 ( r + 3/2)^2 = 9/4 + 2 = 17/4 r +3/2 = +or- sqrt(17/4) r = + sqrt(17/4) - 3/2 or...

    3 Answers · Science & Mathematics · 15/09/2010

  4. ( r − 3)( r + 9)=-9 => r ( r + 9) −3( r + 9)= -9 => r ^2 + 9r −3r − 27 = -9 => r ^2 + 6r − 18 = 0 now...

    4 Answers · Science & Mathematics · 15/12/2013

  5. y = r *sin(T) We know that r = 5*sin(T) which gives sin(T) = r /5 And r ^2 = x^2...

    3 Answers · Science & Mathematics · 03/05/2010

  6. Given r '(t) = t² i + t j + e^(2t) k I am first ...to follow than physics notation. So the above is the same as: r '(t) = <t², t, exp(2t)> r (t) = ∫ r '(t) dt r ...

    2 Answers · Science & Mathematics · 27/01/2012

  7. p( r ) gives you the charge per unit volume of the region. To find the charge... charge in the region = charge per unit volume x volume So dq = p( r ) x dV where dV is the volume of the thin shell. (Note...

    2 Answers · Science & Mathematics · 26/05/2011

  8. r ^2 - 5r - 6r + 30 = 0 r ( r - 5) - 6( r - 5) = 0 ( r - 6)( r - 5) = 0 r - 6 = 0 or r - 5 = 0 r = 6 or r = 5

    3 Answers · Science & Mathematics · 06/02/2011

  9. The DVD- R format was developed by Pioneer in the autumn of 1997. ... system of tracking and speed control used by DVD+ R being less susceptible to interference and error than the LPP system used...

    3 Answers · Computers & Internet · 02/10/2007

  10. Since r ^2 = (- r )^2, we can assume without loss of generality that r ≥ 0. For each fixed r ≥ 0, A( r ) is a circle centered at (0, 0) with radius r . (When r = 0, then A(0) is simply {(0, 0)}.) Hence...

    1 Answers · Science & Mathematics · 27/03/2012

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