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**r**= ± 3 - √3, ± 1 - √3 so**r**IS irrational therefore it must be irrational s = ±√[**r**^2 + (√3)**r**.... Solve the resulting quartic equation:**r**^4 - 4r^2s^2 - 6r^2 + 4s^4 - 12s^2 + 9 = 0 for either "**r**" or...1 Answers · Science & Mathematics · 24/01/2010

Let

**r**= (x(1), x(2), ..., x(n)). So, |**r**...x(2))^2 + ... + (x(n))^2]. Hence,**r**(hat) = (x(1)/√[(x(1))^2 + (x(2))^2...x(1))^2 + ... + (x(n))^2)^(-1/2) = (n-1)/|**r**|. In the case where n = 3, this ...1 Answers · Science & Mathematics · 14/03/2013

The correlation coefficient,

**r**, is a measure of the linear relationship between two variables. If...the data tends to have a negative slope. Positive values for**r**indicate the data tends to have a positive slope. if**r**= 0 we say the ...7 Answers · Science & Mathematics · 03/01/2008

**r**/5 + 6/5 =**r**/7 + 8/7 7r + 42 = 5r + 40 2r = - 2**r**= - 1 Answer:**r**= - 1 Checking: - 1/5 + 6/5 = - 1/7 + 8/7 5/5 = 7/7 1 = 12 Answers · Science & Mathematics · 17/11/2010

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**r**− 3)(**r**+ 9)=-9 =>**r**(**r**+ 9) −3(**r**+ 9)= -9 =>**r**^2 + 9r −3r − 27 = -9 =>**r**^2 + 6r − 18 = 0 now...4 Answers · Science & Mathematics · 15/12/2013

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**r**^2 - 4r - 5)/[5(**r**-5)] = (**r**-5)(**r**+1)/5(**r**-5) simplify by**r**-5: (**r**+1)/5 that's your result :) if you're not sure how to find roots of**r**^2 - 4r - 5, here's how you do it. 1. Find the delta (...5 Answers · Science & Mathematics · 07/10/2011

y =

**r***sin(T) We know that**r**= 5*sin(T) which gives sin(T) =**r**/5 And**r**^2 = x^2...3 Answers · Science & Mathematics · 03/05/2010

this can be written as

**r**^2 + 3r - 2 = 0 Now to solve this you can use the discriminat method (delta = b^2...the method of completing the square.**r**^2 + 3r + (3/2)^2 - (3.2)^2 -2 =0 (**r**+ 3/2)^2 = 9/4 + 2 = 17/4**r**+3/2 = +or- sqrt(17/4)**r**= + sqrt(17/4) - 3/2 or...3 Answers · Science & Mathematics · 15/09/2010

**R**= 1.1926, -4.1926 Try using MathWay.com Hope this helps!4 Answers · Science & Mathematics · 07/04/2013

**R**^2 and**R**^3 are shorthand for RxR and RxRxR, where the operation "x" is a...set of the form X^n is the set of all n-tuples of elements of X. So,**R**^0 would be the set of all 0-tuples of real numbers. However, a 0-tuple is essentially...3 Answers · Science & Mathematics · 30/06/2010