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  1. Well, it is somewhere between R and L, with speakers varying between...not individual letters. So you can't write R along, but you can write syllables that start with R...

    8 Answers · Society & Culture · 27/05/2008

  2. r = ± 3 - √3, ± 1 - √3 so r IS irrational therefore it must be irrational s = ±√[r^2 + (√3)r.... Solve the resulting quartic equation: r^4 - 4r^2s^2 - 6r^2 + 4s^4 - 12s^2 + 9 = 0 for either "r" or...

    1 Answers · Science & Mathematics · 24/01/2010

  3. Let r = (x(1), x(2), ..., x(n)). So, |r...x(2))^2 + ... + (x(n))^2]. Hence, r(hat) = (x(1)/√[(x(1))^2 + (x(2))^2...x(1))^2 + ... + (x(n))^2)^(-1/2) = (n-1)/|r|. In the case where n = 3, this ...

    1 Answers · Science & Mathematics · 13/03/2013

  4. this can be written as r^2 + 3r - 2 = 0 Now to solve this you can use the discriminat method (delta = b^2...the method of completing the square. r^2 + 3r + (3/2)^2 - (3.2)^2 -2 =0 (r + 3/2)^2 = 9/4 + 2 = 17/4 r+3/2 = +or- sqrt(17/4) r = + sqrt(17/4) - 3/2 or...

    3 Answers · Science & Mathematics · 15/09/2010

  5. (r − 3)(r + 9)=-9 => r(r + 9) −3(r + 9)= -9 => r^2 + 9r −3r − 27 = -9 => r^2 + 6r − 18 = 0 now...

    4 Answers · Science & Mathematics · 15/12/2013

  6. y = r*sin(T) We know that r = 5*sin(T) which gives sin(T) = r/5 And r^2 = x^2...

    3 Answers · Science & Mathematics · 03/05/2010

  7. p(r) gives you the charge per unit volume of the region. To find the charge... charge in the region = charge per unit volume x volume So dq = p(r) x dV where dV is the volume of the thin shell. (Note...

    2 Answers · Science & Mathematics · 26/05/2011

  8. r^2 - 5r - 6r + 30 = 0 r(r - 5) - 6(r - 5) = 0 (r - 6)(r - 5) = 0 r - 6 = 0 or r - 5 = 0 r = 6 or r = 5

    3 Answers · Science & Mathematics · 06/02/2011

  9. The DVD-R format was developed by Pioneer in the autumn of 1997. ... system of tracking and speed control used by DVD+R being less susceptible to interference and error than the LPP system used...

    3 Answers · Computers & Internet · 02/10/2007

  10. Since r^2 = (-r)^2, we can assume without loss of generality that r ≥ 0. For each fixed r ≥ 0, A(r) is a circle centered at (0, 0) with radius r. (When r = 0, then A(0) is simply {(0, 0)}.) Hence...

    1 Answers · Science & Mathematics · 27/03/2012

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