"o

**r**bital**r**adius of about 3.29 km (f**r**om the cente**r**of the Ea**r**th)" ?? that is nonsense. ea**r**th**r**adius is 6,371 km "The o**r**bital pe**r**iod fo**r**a satellite is dependent on the mass of the satellite and ________" also w**r**ong, it is not dependent on the mass at all. T = 2π√[R³...1 Answe

**r**s · Science & Mathematics · 13/11/2020...w

**r**ong fo**r**mula. The a**r**ea to use is that of a SPHERE of**r**adius**r**, not a ci**r**cle. So P = I*A = I*4π**r**² ...1 Answe

**r**s · Science & Mathematics · 12/11/2020Cent

**r**ifugal fo**r**ce F = mv²/**r**whe**r**e m - mass of stone v - speed**r**-**r**adius of ci**r**cle Find v such that F exceeds 25N**r**equi**r**ed to b**r**eak a st**r**ing v = √(F**r**/m) v = √(25*2/0.75) = 8.16 m/s1 Answe

**r**s · Science & Mathematics · 12/11/2020...of the ci

**r**cle.(because ai**r**plane is tu**r**ning 90°f**r**om east to south) s = (2 R pi)/4 = R pi / 2 R pi / 2 = v t divide by pi/2 R = 2 v t...1 Answe

**r**s · Science & Mathematics · 12/11/2020... force at the bottom is weight+centrifugal force F = mg + mv^2/

**R**= m (g + v^2/**R**) radius of path**R**is equal to length of rope extract...1 Answe

**r**s · Science & Mathematics · 11/11/2020...box in that point and that is weight+cent

**r**ifugal fo**r**ce F = mg + mv²/ R = m (g + v²/ R ) F = 25 * (9.8 + 11²/7.5) = 648.3 ...1 Answe

**r**s · Science & Mathematics · 11/11/2020... is gravitational constant M is the mass of the Earth

**r**is the distance from the center of the Earth We are not...1 Answe

**r**s · Science & Mathematics · 11/11/2020...the text), it only changes the di

**r**ection of the vecto**r**of speed. a = v² /**r**a = 6670² / 8.92x10⁶ = 4.99 m/s²1 Answe

**r**s · Science & Mathematics · 12/11/2020The simple way is to put mv^2/

**r**= T but this forgets about gravity. The longer way ...1 Answe

**r**s · Science & Mathematics · 12/11/2020... that is in series with 4 and 2.5 = 17.6 and I = E/

**R**= 15/17.5 = 0.85 amps1 Answe

**r**s · Science & Mathematics · 11/11/2020