**R**denotes Radius of loop,**r**denotes radius of sphere a...gt; I (moment of Inertia of sphere) = 2/5mr^2 --> v=**r***w (omega denotes angular velocity) therefore w=v/**r**--> at top of...1 Answe

**r**s · Science & Mathematics · 28/11/2010description of

**r**: look at the figure where potential is required at point P ...)----------------------. (P) .... <-----------**r**--------->**r**& Q are given k = 8.987 X 10^9 N...3 Answe

**r**s · Science & Mathematics · 01/02/2011The

**R**, 16, & 48 are parallel so 1/**R**eq = 1/11 + 1/16 + 1/48 = 0.1742 ... = 8.74Ω So the current through the 3Ω = V/**R**= 3/8.74 = 0.343A and V (3) = 0.343*3 = 1.03V Now...2 Answe

**r**s · Science & Mathematics · 01/06/2010... a short time interval dt, the particle has covered a distance pi

**R**t/T, and so has covered a latitude angle measured from...2 Answe

**r**s · Science & Mathematics · 26/01/2010**r**'(t) = <-2 sin t, 0, 2 cos t>. ||**r**'(t)|| = √(4 sin²t + 4 cos²t) = 2, since sin²t + ...2 Answe

**r**s · Science & Mathematics · 13/11/2011Dependent

**R**and C Go here http://images.google.fr/imgres...1 Answe

**r**s · Science & Mathematics · 12/12/2009**R**(t+h)= 30t+30h-3t^2-6th-3h^2 (substituting t=t+h in your given equation) the average rate of change of**R**(t) would be given by**R**(t+h)-**R**(t)/((t+h)-t) =**R**(t+h...1 Answe

**r**s · Science & Mathematics · 17/12/2012Taking definite integ

**r**ation of given Elect**r**ic field equation fo**r****r**=6m to**r**=8m**r**=8m we have potential diffe**r**ence V.D=ʃ( E.d**r**)=1/24 Nm^3/C**r**=6m2 Answe

**r**s · Science & Mathematics · 08/02/2012The fo

**r**mula is w**r**ong; it should be: E(**r**)= 6000/**r**² This could also be w**r**itten...symmet**r**ic cha**r**ge dist**r**ibution p**r**oduces the elect**r**ic field E(**r**)= 6000/**r**², whe**r**e**r**is in m and E ...5 Answe

**r**s · Science & Mathematics · 07/06/2013**r**=sin 4A**r**= sq root [x^2 +y^2]**r**^2 = x^2 +y^2 since sin 4A = y /**r**so**r**= y /**r r**^2 = y x^2 +y^2 = y ---answer2 Answe

**r**s · Science & Mathematics · 31/05/2011