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1. ### left Ideal and ideal of ring R ?

1) Let L = { r in R | ra = 0}. a) If u and v are in L then (u+v)a...b) If r is in R and u is in L then (ru)a = r (ua) = 0, so ru is in L, which shows that L is...

1 Answers · Science & Mathematics · 22/12/2010

2. ### let R be a relation defined by integers by aRb if a+b is congruent to 0(mod 3). show R is not an equivalence r ?

R is not reflexive. For example, 1 is an integer, but it is not the case that 1 R 1, because 1 + 1 = 2 is not congruent to 0 mod 3. (So... R c, then a R c. Which shows that R is not transitive.)

1 Answers · Science & Mathematics · 09/03/2014

3. ### what does -( r +3)>9 equal?

-( r + 3) > 9 -( r ) > 12 r < -12

5 Answers · Science & Mathematics · 24/11/2010

4. ### What is the minimum value of q( r )....?

Given: q( r ) = r ^3+7r^2-24r+6 To find maximum/minimum, take the derivative: q'( r ) = 3r^2 + 14r - 24 Find the roots: 0 = 3r^2 + 14r - 24 r = (-14 +/- sqrt(14^2 - 4*3*(-24))) / (2*3) r = (-14 +/- sqrt(196 + 288)) / 6 r = (-14...

1 Answers · Science & Mathematics · 15/07/2008

5. ### solve A= 2 pi r ^2 plus 2 pi r h for positive r

A = 2pi r ^2 + 2pi( r )(h) First, move the A to the right hand side. That means one side will be zero. 2pi r ^2 + 2pi( r )(h) - A = 0 This is in the form of a quadratic, as...

2 Answers · Science & Mathematics · 20/08/2008

6. ### How do you antidifferentiate e^( r /4)?

∫9re^( r /4) If we make the substitution u = e^( r /4), we get du = 4e^( r /4), or du/4 = e^( r /4), which we can write as: 9/4...u(ln(u) - 1) Replacing the u's with e^ r /4: e^( r /4) * (ln(e^( r /4)) - 1), which is...

1 Answers · Science & Mathematics · 13/03/2011

7. ### VB : R = A + Csquared?

R =A + C^2 R -A= C^2 + or - sqrt( R -A) =C C=sqrt( R -A) or C=-sqrt( R -A)

2 Answers · Science & Mathematics · 30/08/2007

8. ### Derivative of r = 2∂ √cos∂?

r ' = dr/d∂ = ∂ sqrt(cos∂) - (2∂ sin∂) / 2sqrt(cos∂) = = (2∂ cos∂ - 2∂ sin...

3 Answers · Science & Mathematics · 13/10/2008

9. ### Express (7r+10)/ r ( r +1)( r +2) in partial fractions?

(7 r + 10)/ r ( r + 1)( r + 2) = A/ r + B/( r + 1) + C/( r + 2) A( r + 1...( r + 1) = 7r + 10 r = 0 --> 2A = 10 --> A = 5 r = -1 --> -B = 3 --> B = -3 r = -2 --> 2C = -4...

1 Answers · Science & Mathematics · 03/01/2013

10. ### Algebra, solving for r ?

r ^2 - 5r - 6r + 30 = 0 r ( r - 5) - 6( r - 5) = 0 ( r - 6)( r - 5) = 0 r - 6 = 0 or r - 5 = 0 r = 6 or r = 5

3 Answers · Science & Mathematics · 06/02/2011