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r-(13/3)=(3/2) r=(3/2)+(13/3) r=(9/6)+(26/6) r=35/6 r=5.8333 or 5 and 5/6
3 Answers · Science & Mathematics · 06/11/2009
r+4/r^2-1 × r^2-16/r+1 = (r^3 + 4 - r^2)/r^2 x (r^3 - 16 + r)/r = 1/r^3 x (r^3 + 4 - r^2) x (r^3 - 16 + r) = 1/r^3 x [r^3 x (r^3 - 16 +r) + 4 x (r^3 - 16 +r) - r^2 x (r^3 - 16 +r...
1 Answers · Education & Reference · 18/03/2014
|r+s|^2 = (r+s) dot (r+s) = |r|^2 + 2 (r dot s) + |s|^2 Given |r| = 5, and |s| = 3 we have: = 5^2 + 2 (r dot s) + 3^2 = 34 + 2 (r dot s) since s is perpendicular to (r+s), s...
2 Answers · Science & Mathematics · 18/02/2015
95.5 = (1/(1+r)) * (29.4/r) = (29.4)/{(1+r)(r)}; (95.5) {(1+r)(r)} = 29.4; {(1+r)(r)} = 29.4/95.5 = 0.30785 r^2 +r = 0.30785 r^2 +r - 0.30785 = note that (r +1/2...
1 Answers · Education & Reference · 13/11/2007
r = <x, y, z>, ||r|| = (x^2 + y^2 + z^2)^(-1/2) So, we need to compute curl <...
4 Answers · Science & Mathematics · 02/03/2011
∫r^-3 ln(r)dr u = lnr ; dv = r^-3dr du = (1/r)dr ; v = (-1/2)r^-2 = (-1/2)r^-2 ln(r) + ∫(1/2...1/2)r^-2 ln(r) + [(-1/4)r^(-2)] integrate from 1 to infinity = (-1/2)r^-2 ln(r) + lim(a->infinity) [(-1/4)r^(-2)] integrate from 1 to a...
2 Answers · Science & Mathematics · 23/10/2011
Hi, The DVD+R and DVD-R are competing ...the formats. However, because the DVD-R format has been in use since 1997, it has...
4 Answers · Consumer Electronics · 23/02/2007
r solves x^2 + ax + b = 0 => r*r + a*r = -b => (r+a)*r = -b Since r,a are integers, -b is an integer multiple of r, and so is b, hence r divides b.
3 Answers · Science & Mathematics · 03/02/2013
Hello, The DVD+R and DVD-R are competing ...the formats. However, because the DVD-R format has been in use since 1997, it has...
2 Answers · Consumer Electronics · 12/02/2008
Multiply by r: 1 - 1/2 r^2 = 3/5 r 1/2 r^2 + 3/5 r - 1 = 0 5 r^2 + 6r - 10 = 0 And solve using the quadratic equation.
3 Answers · Science & Mathematics · 05/08/2009