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  1. The required centripetal force is F = mv^2 / r And it acts towards the centre of the circle NOT along...

    2 Answers · Science & Mathematics · 01/07/2019

  2. P * V = n * R * T The unit of pressure is N/m^2. The unit of...

    1 Answers · Science & Mathematics · 23/05/2019

  3. we must use r^2 v= constant. r is the radius and v is the velocity. first condition...4*4=1. This remains a constant. In the second segment r=1. velocity =1 m/s. In the third segment (1/4)^2 v=1. v=16 m/s...

    3 Answers · Science & Mathematics · 15/09/2019

  4. V = kq/r so r = kq/V = 8.98755179e9 * 1e-5/1e4 = 8.98755179e9 * 1e-5/1e4 = = 8.98755179e9...

    3 Answers · Science & Mathematics · 15/09/2019

  5. V/I = R R = 6 / 8 = 0.75 Ohm Now when spinning the net emf...

    3 Answers · Science & Mathematics · 05/01/2019

  6. Diagram: q1. .A. . . B VA = kq/r = 8.99*10^9 * 6.25*10^-8 / 0.150 VB = kq/r = 8.99*10^9 * 6.25*10^-8 / 0...

    3 Answers · Science & Mathematics · 23/05/2019

  7. ...39;s call it α. Then the linear acceleration of the mass is a = α*r = α * 0.119m and the distance the mass travels between the two times...

    3 Answers · Science & Mathematics · 08/07/2019

  8. ...the current that flows through the 24 Ω resistor. I = V ÷ R I = 12 ÷ (7,938 ÷ 137) I = 1,644 ÷ 7,938 This is approximately...

    2 Answers · Science & Mathematics · 21/02/2019

  9. 2 R above the surface is 3 R from the center. So the acceleration of gravity is 1/9 of the surface value. Then force = mass * acceleration = 1950 * (9.80665 / 9) = 2124 newtons.

    1 Answers · Science & Mathematics · 29/10/2019

  10. Relevant equations: torque τ = friction force * radius = f*r = µmgr so τ = 0.03 * 6kg * 9.8m/s² * 0.50m = 0.882 N·m also...

    1 Answers · Science & Mathematics · 11/03/2019

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