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The required centripetal force is F = mv^2 /

**r**And it acts towards the centre of the circle NOT along...2 Answers · Science & Mathematics · 01/07/2019

P * V = n *

**R*** T The unit of pressure is N/m^2. The unit of...1 Answers · Science & Mathematics · 23/05/2019

we must use

**r**^2 v= constant.**r**is the radius and v is the velocity. first condition...4*4=1. This remains a constant. In the second segment**r**=1. velocity =1 m/s. In the third segment (1/4)^2 v=1. v=16 m/s...3 Answers · Science & Mathematics · 15/09/2019

V = kq/

**r**so**r**= kq/V = 8.98755179e9 * 1e-5/1e4 = 8.98755179e9 * 1e-5/1e4 = = 8.98755179e9...3 Answers · Science & Mathematics · 15/09/2019

V/I =

**R****R**= 6 / 8 = 0.75 Ohm Now when spinning the net emf...3 Answers · Science & Mathematics · 05/01/2019

Diagram: q1. .A. . . B VA = kq/

**r**= 8.99*10^9 * 6.25*10^-8 / 0.150 VB = kq/**r**= 8.99*10^9 * 6.25*10^-8 / 0...3 Answers · Science & Mathematics · 23/05/2019

...39;s call it α. Then the linear acceleration of the mass is a = α*

**r**= α * 0.119m and the distance the mass travels between the two times...3 Answers · Science & Mathematics · 08/07/2019

...the current that flows through the 24 Ω resistor. I = V ÷

**R**I = 12 ÷ (7,938 ÷ 137) I = 1,644 ÷ 7,938 This is approximately...2 Answers · Science & Mathematics · 21/02/2019

2

**R**above the surface is 3**R**from the center. So the acceleration of gravity is 1/9 of the surface value. Then force = mass * acceleration = 1950 * (9.80665 / 9) = 2124 newtons.1 Answers · Science & Mathematics · 29/10/2019

Relevant equations: torque τ = friction force * radius = f*

**r**= µmgr so τ = 0.03 * 6kg * 9.8m/s² * 0.50m = 0.882 N·m also...1 Answers · Science & Mathematics · 11/03/2019