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  1. equivalent translating mass of pulley mpe = mp/2 = 4.66/2 = 2.33 kg acceleration a = mb*g/(mb+mpe) = 5.5*9.81/(5.5+2.33) = 6.89 m/sec^2 drop h = a/2+t^2 = 6.89/2*2.17^2 = 16.2 m angular acceleration α = a/r = 6.89/0.376 = 18.3 rad/sec^2

    1 Answers · Science & Mathematics · 21/11/2019

  2. (sin i) / (sin r) = (RI of Y) / (RI of X) = 1.24 / 1 = 1.24 sin r = (sin i) / 1.24 = (sin 14°) / 1.24 = 0.244 / 1.24 = 0.197 r = arcsin 0.107 = 11.36° (ans)

    1 Answers · Science & Mathematics · 19/11/2019

  3. ...*t = ½ * 8.00m/s * 4s = 16 m ◄ a rotation: τ = F*r = I*α and since there is no reason to think that rotation would occur about...

    2 Answers · Science & Mathematics · 14/11/2019

  4. ...the centripetal force is equal to the maximum static friction force: f = mv²/r 5810 N = 1977kg * v² / 57.0m solves to max v = 12.9 m/s ◄ or...

    1 Answers · Science & Mathematics · 13/11/2019

  5. ...22.28 rad/s [ans c] Centripetal acceleration = ω²r ... ... ... [r = radius of circular motion (for the point)] ... ... ... = (6.66)² (0.359) ... ... ... [35...

    1 Answers · Science & Mathematics · 12/11/2019

  6. g = F/m = 2472.8/8 = 309.1 m/sec^2 309.1 = M*G/r^2 r = √ 2.178*10^30*6.674*10^-11/309.1 = 6.86*10^8 m (6.86*10^5 km : very very close to the Sun radius )

    2 Answers · Science & Mathematics · 18/11/2019

  7. ...14200/9.80 = 1450 kg speed of the car V = 43.5/3.6 = 12.08 m/sec curve radius r = 150 m centrip. accel. ac = V^2/r = 12.08^2/150 = 0.973 m/sec^2 centrip. force...

    2 Answers · Science & Mathematics · 18/11/2019

  8. m*V^2/r = m*g*μ mass m cross V = √g*μ*r = √9.8*0.8*19.5 = 12.4 m/sec (44.5 km/h)

    2 Answers · Science & Mathematics · 18/11/2019

  9. a = ω²r 4.37 mi  = 7033 m ω = √(a/r) = √(9.8/7033) = 0.0373 rad/s ω is usually labeled "angular velocity...circle in meters    ω is angular velocity in radians/sec = v/r    a is in m/s²

    1 Answers · Science & Mathematics · 11/11/2019

  10. r(t) = t² i^+ t³ j^ v(t) = 2t i^ + 3t² j^ a(t) = 2 i^ + 6t...

    3 Answers · Science & Mathematics · 11/11/2019

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