Sort by

- Relevance
- |Time

Hi, The DVD+

**R**and DVD-**R**are competing ...the formats. However, because the DVD-**R**format has been in use since 1997, it has...4 Answers · Consumer Electronics · 22/02/2007

**r**solves x^2 + ax + b = 0 =>**r*****r**+ a***r**= -b => (**r**+a)***r**= -b Since**r**,a are integers, -b is an integer multiple of**r**, and so is b, hence**r**divides b.3 Answers · Science & Mathematics · 03/02/2013

Hello, The DVD+

**R**and DVD-**R**are competing ...the formats. However, because the DVD-**R**format has been in use since 1997, it has...2 Answers · Consumer Electronics · 12/02/2008

Multiply by

**r**: 1 - 1/2**r**^2 = 3/5**r**1/2**r**^2 + 3/5**r**- 1 = 0 5**r**^2 + 6r - 10 = 0 And solve using the quadratic equation.3 Answers · Science & Mathematics · 05/08/2009

[(

**r**-2)(**r**+9) -2r(**r**+2)] / [(**r**+2)(**r**+9)] = 6 (**r**^2 + 7r -18 -2r^2 - 4r) / [(**r**+2)(**r**+9)] = 6 (-**r**^2 + 3r - 18) / (**r**^2 + 11r + 18) = 6 -**r**^2 + 3r - 18 = 6(**r**^2 + 11r + 18) = 6r^2 + 66r + 108 7r...1 Answers · Science & Mathematics · 06/05/2010

assume

**r**is any number. {**r**∈**ℝ**} as x becomes sufficiently close to that number, f(x) becomes arbitrarily close to f(**r**). for example: say**r**= 7 which means: f(**r**) = f(7) as x approaches...1 Answers · Science & Mathematics · 14/10/2013

**R**=(ab)/(a+b)**R**(a+b) = ab Ra + Rb = ab Rb = ab - Ra Rb = a(b-**R**) a = (Rb)/(b-**R**)1 Answers · Education & Reference · 01/11/2008

Let f:

**R**->**R**' be an isomorphism. If**R**is commutative, and a... of**R**', then a' = f(a) and b' = f(b) for some a,b in**R**. Then we have: a'b' = f(a)f(b) = f(ab) = f(ba) = f(b)f(a) = b'...2 Answers · Science & Mathematics · 05/12/2012

**r**^2+**r**=A/(2ph)? If so, then**r**^2+**r**-A/(2ph)=0=>**r**=[-1+/-sqrt(1+2A/(ph)]/2 =>**r**=[-1+sqrt(1+2A/(ph))]/2 or**r**=[-1-sqrt(1+2A/(ph))]/22 Answers · Science & Mathematics · 20/09/2013

Use the facts that sin(θ) = y/

**r**and**r**= √(x^2 + y^2). First, for**r**= 3sin(θ):**r**= 3sin(θ)**r**= 3(y/**r**... is a circle. In the subject line, I'll assume you mean**r**= sin(3θ) and not**r**= sin^3 (θ). You'll have to use a trig identity for...1 Answers · Science & Mathematics · 19/05/2007