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... what you are to solve for is V of the battery and

**R**of the battery. When the resistors are in parallel the effective...6 Answers · Science & Mathematics · 27/02/2019

change in energy =

**R**(1/3² - 1/5²) = 1.55e-19 J and change in energy = hv / λ so λ = hv / change in energy = 6.626e−34J·s * 2.998e8m/s / 1.55e-19J λ = 1.282e-6 m = 1.282 µm = 1282 nm2 Answers · Science & Mathematics · 14/06/2019

Power = V²/

**R**= (1.5+1.5)²/10Ω = 0.9W <----- (a) 2/3 * 0...1 Answers · Science & Mathematics · 09/06/2019

A/ torque τ =

**r**x F = 0.10m * 10N = 1.0 N·m B/ For a solid cylinder...1 Answers · Science & Mathematics · 12/06/2019

first get total

**R**as seen by the battery 1 in parallel with 7.8 is 7.8/8.8 = 0.886... which produces current thru 7.8 Ω of I = E/**R**= 0.094/7.8 = 0.012 amp or 12 mA1 Answers · Science & Mathematics · 04/03/2019

V = √(GM/

**R**) V = √( (6.673e-11)(5.97e24) / (3• 6.37e6) ) = ______ m/s Satellite...6.673e-11 Nm²/kg² M is mass of central body in kg**R**is radius of orbit in m earth radius 6,371 km = 6.37e6 meters earth...2 Answers · Science & Mathematics · 08/05/2019

dA^ =

**r**^ dh dφ E = k q**r**^ / r³ then the angle θ between the electric field vector E^ and the vector dA^ is null1 Answers · Science & Mathematics · 12/09/2019

Vorb^2/

**R**= Ms*G/**R**^2 Vorb^2*4.75*10^10 = 8.05*10^29*6.67*10...1 Answers · Science & Mathematics · 01/06/2019

tangential velocity Vt = ω*

**r**= 23*1.75 m/sec Ke = m/2*V^2 = 18/2*(23*1.75)^2 = 14,581 joule or J = m***r**^2 = 18*49/16 KE = J/2*ω^2 = 9*49/16*23^2 = 14,581 joule1 Answers · Science & Mathematics · 17/10/2019

Ipeak = Vr/

**R**= 60/300 = 0,20 A Vℓ = X*I = ω*L*I = 200...2 Answers · Science & Mathematics · 06/08/2019