Sort by

- Relevance
- |Time

Note that the line at the bottom (connecting points (-4, -3) to (1, 1)) has equation y = 4x/5 + 1/5. Then, the

**r**egion can be desc**r**ibed by y = 4x/5 + 1/5 to y = 3 with x in [-4, 1]. In othe**r**wo**r**ds, the integ**r**al equals ∫(x = -4 to 1) ∫(y = 4x/5 + 1/5 to 3...1 Answers · Science & Mathematics · 17/05/2019

...’s my version. To find curvature, I’ll use κ = ||

**r**’(t) X**r**’’(t)||/||**r**’(t)||³ (equation 1) <t²...3 Answers · Science & Mathematics · 30/05/2019

The natural domain of the function is

**ℝ**Neither of the given options is correct. {x ∈**ℝ**} or just**ℝ**is what it should be.3 Answers · Science & Mathematics · 08/08/2019

profit = revenue - costs p(x) =

**r**(x) - c(x) = 90x - (0.0002x³ - 0.1x² + 20x + 6000) = -0.0002x³...1 Answers · Science & Mathematics · 09/02/2019

**r**= 3 / [1 - sin(θ)]**r**= 3 + rsin(θ) r² = 9 + 6rsin(θ) + r²sin²(θ) x²...answer. Yahoo might not save my revised answer though.**r**= 3 / [1 - 3sin(θ)]**r**= 3 + 3rsin(θ) r² = 9 + 18rsin(θ) + ...3 Answers · Science & Mathematics · 21/08/2019

A) f:

**R**->{y| y is real & y>1} y=sqr(x^2+1) => f^-1: {x| x is...even if the branches are discussed separately. B) f:**R**-{3}->**R**-{1) y=(x+3)/(x-3) => f^-1:**R**-{1}->**R**-{3} y=3...2 Answers · Science & Mathematics · 16/07/2019

**r**_1 = 1 - cos(Θ) ;**r**_2 = cos(Θ) What is Θ when**r**_1 =**r**_2... the solution in the range [0, π]. So what is "**r**"**r**_2 = cos(π / 3) = 1 / 2 which is the same value as**r**_1...3 Answers · Science & Mathematics · 05/05/2019

L + 17 =

**R**- 17 : 17 from right to left = same in both hands 2(L - 17) =**R**...right as in left Subtract first equation from second to eliminate**R**and solve for L 2(L-17) - (L+17) =**R**+17 - (**R**-17...2 Answers · Science & Mathematics · 29/05/2019

**r**= 3 / (3 + 3sin(t))**r**= 1 / (1 + sin(t))**r*** (1 + sin(t)) = 1**r**+ rsin(t) = 1 sqrt(x^2 + y^2) + y = 1 sqrt(x^2 + y^2) = 1 - y x^2 + y^2 = 1 - 2y + y^2 x^2 = 1 - 2y 2y = 1 - x^2 y = (-1/2) * x^2 + (1/2) It's a parabola1 Answers · Science & Mathematics · 28/06/2019

**r**= < t , t² , 0 > ;**r**' = < 1 , 2t , 0 > ;**r**' ' = < 0 , 2 , 0...1 Answers · Science & Mathematics · 20/05/2019