Yahoo Web Search

  1. Sort by

  1. r^2+3r-2 = 0 Factorize the equation. then (r+1)(r-3) = 0 Therefore, r = -1 & 3

    3 Answers · Science & Mathematics · 14/10/2008

  2. description of r: look at the figure where potential is required at point P ...)----------------------. (P) .... <-----------r---------> r & Q are given k = 8.987 X 10^9 N...

    3 Answers · Science & Mathematics · 01/02/2011

  3. I = (2V/R) + 2r I - (2V/R) = 2r r = (1/2) * [I - (2V/R... - IR r = (2V - IR) / 2I r = (V/I) - (R/2)

    3 Answers · Science & Mathematics · 16/01/2014

  4. C=K(Rr/R-r) Divide both sides by K: C/K = (Rr... = Cr/K Extract R: R(C/K - r) = Cr/K Divide both sides by (C/K - r...

    4 Answers · Education & Reference · 05/10/2009

  5. If f is a *surjective* homomorphism from R to R' then R/ker(f) and R'...ker(f) to f(x) is an isomorphism--- so, in particular, R/ker(f) is isomorphic to f(R). But...

    1 Answers · Science & Mathematics · 24/07/2011

  6. r-(13/3)=(3/2) r=(3/2)+(13/3) r=(9/6)+(26/6) r=35/6 r=5.8333 or 5 and 5/6

    3 Answers · Science & Mathematics · 06/11/2009

  7. r+4/r^2-1 × r^2-16/r+1 = (r^3 + 4 - r^2)/r^2 x (r^3 - 16 + r)/r = 1/r^3 x (r^3 + 4 - r^2) x (r^3 - 16 + r) = 1/r^3 x [r^3 x (r^3 - 16 +r) + 4 x (r^3 - 16 +r) - r^2 x (r^3 - 16 +r...

    1 Answers · Education & Reference · 18/03/2014

  8. |r+s|^2 = (r+s) dot (r+s) = |r|^2 + 2 (r dot s) + |s|^2 Given |r| = 5, and |s| = 3 we have: = 5^2 + 2 (r dot s) + 3^2 = 34 + 2 (r dot s) since s is perpendicular to (r+s), s...

    2 Answers · Science & Mathematics · 18/02/2015

  9. 95.5 = (1/(1+r)) * (29.4/r) = (29.4)/{(1+r)(r)}; (95.5) {(1+r)(r)} = 29.4; {(1+r)(r)} = 29.4/95.5 = 0.30785 r^2 +r = 0.30785 r^2 +r - 0.30785 = note that (r +1/2...

    1 Answers · Education & Reference · 13/11/2007

  10. r^-3 ln(r)dr u = lnr ; dv = r^-3dr du = (1/r)dr ; v = (-1/2)r^-2 = (-1/2)r^-2 ln(r) + ∫(1/2...1/2)r^-2 ln(r) + [(-1/4)r^(-2)] integrate from 1 to infinity = (-1/2)r^-2 ln(r) + lim(a->infinity) [(-1/4)r^(-2)] integrate from 1 to a...

    2 Answers · Science & Mathematics · 23/10/2011

  1. Try asking your question on Yahoo Answers