Yahoo Web Search

  1. Sort by

  1. ...5+x)/10 = x/y When y = 3 m, solve this and get x = 2.143 m differentiate w/r/t time, using the quotient rule on the RHS: 0.1 * dx/dt = (1/y²...

    2 Answers · Science & Mathematics · 07/11/2019

  2. ...the car in a circle at any given speed we need a centripetal acceleration of v^2 / r  = 4^2/523 To accelerate the car along a path we require an acceleration = dv/dt...

    1 Answers · Science & Mathematics · 05/11/2019

  3. ac = Vt^2/r = 103^2/106 = 100 m/sec^2 acceleration a = g-ac = 4-100 = 96 m/sec^2 reading = zero

    2 Answers · Science & Mathematics · 04/11/2019

  4. ...and the speed of the center of mass are related by the definition ω = v/r The kinetic energy is the sum of the translational and rotational ...

    1 Answers · Science & Mathematics · 03/11/2019

  5. ...the shortest distance from the axis to our point of interest is r = 6.37 x 10^6 cos45 = 4.50 x 10^6 m The angular velocity of earth is...

    1 Answers · Science & Mathematics · 31/10/2019

  6. 2 R above the surface is 3 R from the center. So the acceleration of gravity is 1/9 of the surface value. Then force = mass * acceleration = 1950 * (9.80665 / 9) = 2124 newtons.

    1 Answers · Science & Mathematics · 29/10/2019

  7. ...moment of inertia in kg•m²I = cMR²    M is mass (kg), R is radius (meters)    c = 1 for a ring or hollow cylinder    c = 2/5...

    1 Answers · Science & Mathematics · 20/10/2019

  8. ...see http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/curloo.html#c3 with z = R. Simplifying gives: B = μ₀R²I/(2(R²...

    2 Answers · Science & Mathematics · 18/10/2019

  9. angular speed ω = V/r = 18/(1/3) = 54 rad/sec angular acceleration α = at/r = 1.22/(1/3) = 3.66 rad/sec^2 angle Θ = ω*t+ α/2*t^2 = 54*0.7+1.83*0.7^2 = 38.70 radians ... rounded up to 39

    1 Answers · Science & Mathematics · 17/10/2019

  10. tangential velocity Vt = ω*r = 23*1.75 m/sec Ke = m/2*V^2 = 18/2*(23*1.75)^2 = 14,581 joule or J = m*r^2 = 18*49/16 KE = J/2*ω^2 = 9*49/16*23^2 = 14,581 joule

    1 Answers · Science & Mathematics · 17/10/2019

  1. Try asking your question on Yahoo Answers