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  1. ...'s all you can do in some cases. P * V = n * R * T P * V / T = n * R Since both ...

    1 Answers · Science & Mathematics · 25/11/2019

  2. By the formula you provide, r = 2T / hpg = 2*0.07199kg/s² / (0.17m * 1000kg/m³ * 9.8m/s²) r = 8.6e-5 m so the diameter d = 2r = 1.7e-4 m = 0.17 mm Hope this helps!

    1 Answers · Science & Mathematics · 22/11/2019

  3. moment od inertia J = m/2*r^2 = 0.34*7.9^2/10^4 = 0.00212 kg*m^2 angular acceleration α1 = 2PI/60*n/t1...

    1 Answers · Science & Mathematics · 23/11/2019

  4. ... If the inductance L is 1.1 mH and the resistance R is 20 Ω, f = 1/(2π√(LC)) = 760000 2π√(LC) = 1/760000...

    4 Answers · Science & Mathematics · 21/11/2019

  5. equivalent translating mass of pulley mpe = mp/2 = 4.66/2 = 2.33 kg acceleration a = mb*g/(mb+mpe) = 5.5*9.81/(5.5+2.33) = 6.89 m/sec^2 drop h = a/2+t^2 = 6.89/2*2.17^2 = 16.2 m angular acceleration α = a/r = 6.89/0.376 = 18.3 rad/sec^2

    1 Answers · Science & Mathematics · 21/11/2019

  6. (sin i) / (sin r) = (RI of Y) / (RI of X) = 1.24 / 1 = 1.24 sin r = (sin i) / 1.24 = (sin 14°) / 1.24 = 0.244 / 1.24 = 0.197 r = arcsin 0.107 = 11.36° (ans)

    1 Answers · Science & Mathematics · 19/11/2019

  7. ...*t = ½ * 8.00m/s * 4s = 16 m ◄ a rotation: τ = F*r = I*α and since there is no reason to think that rotation would occur about...

    2 Answers · Science & Mathematics · 14/11/2019

  8. ...the centripetal force is equal to the maximum static friction force: f = mv²/r 5810 N = 1977kg * v² / 57.0m solves to max v = 12.9 m/s ◄ or...

    1 Answers · Science & Mathematics · 13/11/2019

  9. ...22.28 rad/s [ans c] Centripetal acceleration = ω²r ... ... ... [r = radius of circular motion (for the point)] ... ... ... = (6.66)² (0.359) ... ... ... [35...

    1 Answers · Science & Mathematics · 12/11/2019

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