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  1. F = mv²/ R a) F = 208(34²)/33 = 7,286.3030... ≈ 7.3 kN b) F = 208(34²)/24 = 10,018.6666... ≈ 10 kN

    1 Answers · Science & Mathematics · 14/09/2020

  2. ...surface. Your Gaussian surface is, of course, a sphere of radius r centered on your charged spherical shell. The ...

    1 Answers · Science & Mathematics · 09/09/2020

  3. F = k e^2 / r ^2 F = 9x10^9 * (1.602×10^−19)^2 / (1x10^−11)^2 F = 2.31 × 10^-6 N where e =  1.602×10^−19 C is charge od proton k = 9x10^9 N m^2/C^2 is Coulomb's constant

    1 Answers · Science & Mathematics · 17/09/2020

  4. ...potential is constant and so the field (which is the derivative of potential w/ r /t r ) is zero -- E = dV/dr = d(-ke*Q/ R )/dr = 0...

    1 Answers · Science & Mathematics · 18/09/2020

  5. Take the derivative of the given equation w/ r /t time: dP/dt * V^1.4 + P * 1.4*V^0.4 * dV/dt...

    1 Answers · Science & Mathematics · 09/09/2020

  6. ...surface. and ε₀ = 8.85e-12 C²/N·m² A) At r = 0.021 m, the enclosed charge is Q = (4.10 - 2.50) mC...

    1 Answers · Science & Mathematics · 09/09/2020

  7. ... 1) ΔL = 1.0e-5 * 20 * (-27 - 25) = 0.0104 m 2) Δ r = 17e-6 * 6.0m * 90K = 0.00918 m = 9.18 mm 3) using α = 24e-6, 0...

    1 Answers · Science & Mathematics · 14/09/2020

  8. ...-Vi)/2 = (48-20)/2 = 14 m/sec^2 accel. time ta = 2.0 sec retardation r = (0-48)/3 = -16 m/sec^2 retard. time tr = 3.0 sec distance computation : S1...

    2 Answers · Science & Mathematics · 07/09/2020

  9. ...the speed is 310km/h = 86 m/s and the distance covered was d = π r = π*210m = 660 m and so from v² = u² + 2as we get (when initial speed...

    2 Answers · Science & Mathematics · 24/08/2020

  10. ... then the light spreads to the surface of a sphere.  Area = 4 pi() r ^2  and if, at the radius of 4.1m, the intensity on EACH square metre...

    1 Answers · Science & Mathematics · 07/09/2020

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