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  1. Well, it is somewhere between R and L, with speakers varying between...not individual letters. So you can't write R along, but you can write syllables that start with R...

    8 Answers · Society & Culture · 27/05/2008

  2. Let r = (x(1), x(2), ..., x(n)). So, |r...x(2))^2 + ... + (x(n))^2]. Hence, r(hat) = (x(1)/√[(x(1))^2 + (x(2))^2...x(1))^2 + ... + (x(n))^2)^(-1/2) = (n-1)/|r|. In the case where n = 3, this ...

    1 Answers · Science & Mathematics · 13/03/2013

  3. this can be written as r^2 + 3r - 2 = 0 Now to solve this you can use the discriminat method (delta = b^2...the method of completing the square. r^2 + 3r + (3/2)^2 - (3.2)^2 -2 =0 (r + 3/2)^2 = 9/4 + 2 = 17/4 r+3/2 = +or- sqrt(17/4) r = + sqrt(17/4) - 3/2 or...

    3 Answers · Science & Mathematics · 15/09/2010

  4. (r − 3)(r + 9)=-9 => r(r + 9) −3(r + 9)= -9 => r^2 + 9r −3r − 27 = -9 => r^2 + 6r − 18 = 0 now...

    4 Answers · Science & Mathematics · 15/12/2013

  5. y = r*sin(T) We know that r = 5*sin(T) which gives sin(T) = r/5 And r^2 = x^2...

    3 Answers · Science & Mathematics · 03/05/2010

  6. r^2 - 5r - 6r + 30 = 0 r(r - 5) - 6(r - 5) = 0 (r - 6)(r - 5) = 0 r - 6 = 0 or r - 5 = 0 r = 6 or r = 5

    3 Answers · Science & Mathematics · 06/02/2011

  7. The DVD-R format was developed by Pioneer in the autumn of 1997. ... system of tracking and speed control used by DVD+R being less susceptible to interference and error than the LPP system used...

    3 Answers · Computers & Internet · 02/10/2007

  8. Since r^2 = (-r)^2, we can assume without loss of generality that r ≥ 0. For each fixed r ≥ 0, A(r) is a circle centered at (0, 0) with radius r. (When r = 0, then A(0) is simply {(0, 0)}.) Hence...

    1 Answers · Science & Mathematics · 27/03/2012

  9. R=3a^2b Since b is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. 3a^2b=R Divide each term in the equation by 3a^(2). 3a^2b/3a^2=R/3a^2...

    2 Answers · Education & Reference · 16/07/2013

  10. 1) r = 4∙sin(θ) r = 0 for 4∙sin(θ) = 0 sin(θ) = 0 θ = 0 or θ = π r' = 4∙cos(θ) r' = 0 for 4∙cos(θ) = 0 cos...or θ = π 3 + 2∙cos(0) = 5 3 + 2∙cos(π) = -5 so r-max at θ = 0 Graph: http://i48.tinypic.com/doauci...

    1 Answers · Science & Mathematics · 22/05/2012

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