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  1. ...the C-H bonds next to the carbonyl, so the final product will be PhC=OCI2CH3. Hope that helps!

    1 Answers · Science & Mathematics · 24/02/2008

  2. CH3C=OCH3 + PhC=OH ----> CH3C=OCH2C*H(OH)Ph; C...

    1 Answers · Science & Mathematics · 15/09/2008

  3. To prepare PhC(CH3)2OH you use PhCO2CH3 and CH3MgBr To prepare CH3CH2C(CH3)2OH your method is correct.

    3 Answers · Science & Mathematics · 13/03/2016

  4. Dieckmann condensation would give... PhC(=O)-CD(CH3)-C(=O)-cyclicC5H10...

    2 Answers · Science & Mathematics · 19/07/2010

  5. ...in your calculation to prevent errors Firstly, the eqn: PhC=OCH3 + 4NaClO ----> PhC=OOH + 4NaCl + ...

    1 Answers · Science & Mathematics · 11/11/2008

  6. ...salt can be attacked by another equivalent of ethyl lithium, which forms PhC(OLi)2-Et. When you learned about Grignards...

    3 Answers · Science & Mathematics · 13/04/2011

  7. In order to make benzoin you have to create the [PhC=O]- ion, which can only persist in basic media. Since benzoic acid is acidic, it will destroyed the base and lower the yield of the reaction.

    1 Answers · Science & Mathematics · 22/02/2013

  8. ... reagent: Ph-C≡CH + CH3CH2MgBr → (PhC≡C^-)MgBr + CH3CH3 Acid1 + conjugate base2 → conjugate base1...

    1 Answers · Science & Mathematics · 28/06/2014

  9. ... example, if you were trying to use PhMgBr to make PhC(OH)Me2, 2-phenyl-2-propanol, then a side reaction could well produce benzene...

    3 Answers · Science & Mathematics · 07/03/2009

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