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  1. PF of 25 = 5^2 PF of 135 = 5*27 LCM = 5^2*7 therefore GCF is 5 and LCM = 175 PF of 15 = 3*5 PF of 40 =2^3*5 LCM = 2^3*3*5 Therefore...

    3 Answers · Science & Mathematics · 01/11/2012

  2. Pf(3.5 - 2.575*48/sqrt(256) < μ < 3.5 - 2.575*48/sqrt(256)) = 1 - 0.01 Pf(3.5 - 7.725 < μ < 3.5 + 7.725) = 0.99 Pf...

    1 Answers · Science & Mathematics · 21/02/2013

  3. Let tje s[eed pf tje plane be x mph and the calm air and let the sped of the wind be y mph by the problem...

    5 Answers · Science & Mathematics · 02/03/2007

  4. ..., I shall attempt it from the first principles. PF + PF' = 8 => √[x^2 + (y - √5)^2] + √[x^2 + (y + √5)^2] = 8 =>...

    1 Answers · Science & Mathematics · 20/05/2010

  5. pf = 3gf 2pg = gg pf+2pg = 14 gf+2gg = 18 3gf+gg = 14 3gf+6gg = 54 -------------------------- 5gg = 40 gg...

    1 Answers · Science & Mathematics · 26/11/2011

  6. Pf: cosx / sinx + sinx / cosx =cosx*cosx / sinx*cosx + sinx*sinx / cosx*sinx =cos^2(x...

    3 Answers · Science & Mathematics · 23/06/2012

  7. ...log of both sides of the equation, separate out (Vi), then exponentiate: (Pf) (Vf)^x = (Pi) (Vi)^x log(Pf) + xlog(Vf) = log...

    2 Answers · Science & Mathematics · 26/10/2007

  8. Slope PF = (1 + 3) / (-5 +1) = 4/4 = 1 Slope ST = (2 + 2) / (-2 + 2) = 4/4 = 1...

    1 Answers · Science & Mathematics · 02/01/2013

  9. Use induction for both. Pf bounded above by 2/3: Base: (n=1) 2^1...by induction hypothesis QED Pf bounded below by -2/3: Base: (n=1) 2/5...

    1 Answers · Science & Mathematics · 23/05/2008

  10. R(p) = pf(p) Use derivative of product df(x)*g(x)/dx = df/dx * g(x) + f(x) * dg/dx R'(p) = f(p) + p f'(p) R'(16) = f(16) + 16*f'(16) = 9000 + 16 * (-340) = 3560.

    1 Answers · Science & Mathematics · 08/05/2013

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