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  1. yes, your equation is correct. area=(capacitance*distance)/epsilon_0 area= (pi)r^2 convert everything to meters and convert the capacitance from picoF to just F (simply multiple the given 1.80 times 10^-12) make sure you convert your final answer to...

    1 Answers · Science & Mathematics · 07/01/2013

  2. 120 watts per hour is 120/ 1000 = .12 kilowatt hour. If electricity cost about 12 cents a kilowatt hour this is about 1.44 cents an hour

    3 Answers · Science & Mathematics · 03/09/2009

  3. Assuming the parts are in series (You should state that), and assuming the circuit is driven by a voltage source that does not change amplitude as frequency changes, then the max current is at resonance, and the reactance of the L and C...

    2 Answers · Science & Mathematics · 06/12/2011

  4. The impedance of the line is Sqrt(0.01^2 + 0.08^2) =0.0806 ohms The current for the 20 KVA is I =20000 / 125 = 160 amps The votage drop in the line is E = I * R = 160 * 0.0806 = 12.896 volts This...

    1 Answers · Science & Mathematics · 04/05/2011

  5. You need to provide full details before this can be answered, NOT a bunch of meaningless hints. .

    1 Answers · Science & Mathematics · 02/06/2011

  6. The power factor is 0.97 The 100 KW load at 0.8 power factor has 75 KVAR. 300 KW with 75 KVAR has 309.23 KVA. Power factor is KW / KVA or 300 / 309.23 =0.97

    1 Answers · Science & Mathematics · 21/02/2011

  7. All AC circuits (unless the load is purely resistive) have both resistance and reactance. We pay only for the current used by the resistive portion of the current. This part is called watts. A watt hour meter only registers...

    5 Answers · Science & Mathematics · 05/10/2011

  8. The winding ratio would be the same. It's dependent strictly on primary and secondary voltage requirements. You would be able to make do with a smaller iron core, though. This would reduce the overall size and weight of the transformer. However: the...

    2 Answers · Science & Mathematics · 23/06/2010

  9. Real power = (VA)*)pf) = (300,000VA)*(.7) = 210,000 Watts VA = (real power...real power is constant at 210kW kVARs at a .8 pf = (tan arc cos .8)*(210kW) = 157.5kVAR kVARs...

    2 Answers · Science & Mathematics · 30/09/2011

  10. just guessing: 33000 pF or 33 nF 100000 pF or 100 mF or 0.1 µF 4700...

    1 Answers · Science & Mathematics · 03/12/2010

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