Yahoo Web Search

  1. ... linear momentum, but not kinetic energy so Pi = Mv0     Pf = (M + m)vf  --> Pi = Pf vf = Mv0/(M + m...

    1 Answers · Science & Mathematics · 23/02/2021

  2. ...any point on the parabola Q(4, y) ... the projection of P onto the directrix PF = PQ PF² = PQ² (x + 2)² + (y - 5)² = (x - 4...

    4 Answers · Science & Mathematics · 22/02/2021

  3. . f( x ) = 8x² + 2x ( a ) f( x ) = 8x² + 2x f( x + h ) = 8( x + h )² + 2( x + h ) = 8x² + 16xh + 8h² + 2x + 2h = 8x² + 2x + 16xh + 8h² + 2h slope = [ f( x + h ) - f( x ) ] / h = [ ( 8x² + 2x + 16xh + 8h² + 2h ) - ( 8x² + 2x ) ] / h = ( 16xh...

    1 Answers · Science & Mathematics · 03/09/2019

  4. Octants are stone age. Just say x<0? Before starting, you make the argument that the entire region is symmetric about xz plane and the integrand is an odd function of y, so you can just remove the +y part. The integral on the part of the region where y>0...

    2 Answers · Science & Mathematics · 05/05/2019

  5. Hint: a/ vertex at (h,k) p = -4 (y-k)^2 = 4p(x-h) b/ P(x,y) on the parabola, PH=distance to the directrix , F = focus point PH = PF

    1 Answers · Science & Mathematics · 22/09/2018

  6. ...(x,y) to F'(-c,0) is √[ (x+c)² + y² ] PF = √[ (x-c)² + y² ] = √[ x² - 2xc + c² + b²...

    2 Answers · Science & Mathematics · 09/01/2018

  7. ...with named endpoints: PT is the tangent segment, and PF is the entire secant segment, with PN the "external" part of the...

    1 Answers · Science & Mathematics · 03/12/2017

  8. ... PQ is a focal chord, then PQ has the same slope as PF (or QF) Slope PQ: ∆y/∆x = ¾ Slope...

    2 Answers · Science & Mathematics · 03/04/2018

  9. The only tricky part is getting your values for P and t interpreted correctly. P is the population in *thousands*, so you want to know when P = 350. That will correspond to a population of 350,000. Plug that into...

    4 Answers · Science & Mathematics · 10/09/2017

  10. OB = OD (radius) OC = PF (radius) BC = DF (given) => △OBC = △ODF

    2 Answers · Science & Mathematics · 16/08/2017

  1. Try asking your question on Yahoo Answers