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Total Real power = 100W + (.74 x 269)W = 299W Capacitive Imaginary power = 50 VAR Inductive imaginary power = [sin (arc cos .74) x 269VA] VAR = 180.93 VAR Total imaginary power = 180.93...

1 Answers · Science & Mathematics · 29/01/2010

... - milli ampere uF - micro farad

**pF**- picofarad these follow just a blind nomenclature (to say...capacitance is impossible...... therefore we go for**pF**,nF,uF example for unit nano is...3 Answers · Science & Mathematics · 29/02/2008

**PF**= P / S where**PF**= power factor P = active (true... = apparent power (VA, volts amps) S = P/**PF**S = E*I E*I = P/**PF**I...3 Answers · Science & Mathematics · 12/06/2011

3.0

**pF**= 3 x 10^(-12) F surface charge densities of +/- 1.0nC/mm^2...1 Answers · Science & Mathematics · 13/03/2009

**Pf**= 500 kPa Rf = 2 m Vf = 4/3*π*Rf^3 = 33.4933 m^3...1 Answers · Science & Mathematics · 16/10/2010

... / I = Amps /W = Watts /

**PF**= Power Factor / Eff = ... I x E 1000 I x E x**PF**1000 I x E x**PF**1000 I x...2 Answers · Science & Mathematics · 14/03/2007

** The

**PF**of the circuit is 0.238 Leading Explained: ω = 360 rad/s...628.25 = 0.238 = ANSWER As Xc exceeds Xʟ the**pf**is Leading. Has this helped? Clarification...2 Answers · Science & Mathematics · 20/04/2013

**pf**= cos x x = cos ^ -1**pf**x = 43.945 375 = 120 (I) (0.72) I = 4.34 A RP = 120 (4.34) sin 43.945 AP= sqrt(Power^2 + RF^2) Z=R+jXL inductive2 Answers · Science & Mathematics · 01/02/2011

**pf**= cos φ = 0.3 sin φ = √1-0.3^2 = 0.954 = X/Z Z = X/sin φ = 40/0.954 = 41.93 ohm 0.3 = R/Z R = Z*0.3 = 41.93*0.3 = 12.58 ohm....10 ohm is wrong !!!2 Answers · Science & Mathematics · 26/12/2014

ower factor (

**pf**) is essentially the the ration of the true power to the apparent power. that ...) = VrmsxIrms For computation, it turns out that**pf**is just equal to cos (theta) where theta is the angle of the circuit'...1 Answers · Science & Mathematics · 10/10/2007