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1. ### The capacitance per unit length of a coaxial cable, made of two concentric cylinders, is 50 pF/m. What is the?

From formula c = 2πε / ln(r2/r1) we obtain r2 = r1 e^(2πε/c) = 1.0 x e^(6.28 x 8.85x10^-12 / 50x10^-12) = 3.0 mm

2 Answers · Science & Mathematics · 31/12/2012

2. ### A parallel-plate capacitor has a plate area of 15.3 cm2 and a capacitance of 3.1 pF. The permittivity of a vac?

C = ε.S/e → e = ε.S/C = 8,85E-12*15,2E-4/3,1E-12 = 0,004339355 m → e = 4,34 mm @+ ;)

2 Answers · Science & Mathematics · 18/06/2011

3. ### How do you convert 4.425 pF to nC for capacitance??

For parallel plate, C = E * A/d A = 4 cm^2 = 0.0004 m^2 d = 2mm = 0.002 m E = Eo * (Er of Water) = 8.85*10^-12 * 80 C = 8.85*10^-12 * 80 * .0004/0.002 = 1.416e-10 = 141.6pF charge = q = C*V q = 141.6*10^-12 * 5 = 0...

1 Answers · Science & Mathematics · 07/03/2008

4. ### The speed pf light... There's bioluminesent sea creatures, does light leave their bodies at the speed of ligh

The speed of the light leaving this creature under water is the same as the speed of light in vacuum. Light only exists in vacuum, this is something that people get confused alot. In a medium, that is, in an actual molecule of the substance, not in between, the light...

9 Answers · Science & Mathematics · 10/08/2006

5. ### Each plate on a 2700 pF capacitor carries a charge with a magnitude of 1.40 * 10^-8 C.?

Q = CV V = Q/C = 1.4e-8 / 2700e-12 = 5.2 volts E = ½CV² E = ½(2.7e-9)(5.2)² = 3.63e-8 Joules .

1 Answers · Science & Mathematics · 27/10/2012

6. ### convert the speed pf light, 3.0 x 10 to the 8th power m/s, to km/day?

3.0x10^8=100million metres/s ---> 100000km/s 86400 seconds in a day 100000km/s*86400s=8640000000km/day OR 8.64 x 10 to the 7th power so light travels 8.64 x 10 to the 7th power kilometres in a day

1 Answers · Science & Mathematics · 05/09/2009

7. ### A 7561.0 pF capacitor holds 0.173 microCoulombs of charge. What is the voltage across the capacitor?

Capacitance C = Q/V => V = Q/C C = 7561.0×10^-12 F Q = 0.173×10^-6 C => V = 0.173×10^-6 / 7561.0×10^-12 = 22.88 V

1 Answers · Science & Mathematics · 26/02/2015

8. ### Each plate on a 3665 pF capacitor carries a charge with a magnitude of 1.8 10-8 C.?

A. V = Q/C = 1.8E-8/3665E-12 = 4.911323 V B. E = V/d = 4.911323/5.48E-4 = 8962.2688 V/m

1 Answers · Science & Mathematics · 09/02/2010

9. ### Each plate on a 3665 pF capacitor carries a charge with a magnitude of 1.8 10-8 C.?

Volume V = 20*30*thck = 600*thck dm^3 Volume V = mass/density = 324/2.7 = 120.0 dm^3 thickness = 120/600 = 0.200 dm = 2.00 cm

1 Answers · Science & Mathematics · 16/12/2016

10. ### A 100.0 pF capacitor consists of two circular plates of radius 0.40 mm. How far apart are the plates?

The formula to be used is the parallel plate capacitor formula: C = ε0 S / d where C = capacitance, S plate area, d plate distance. Then: d = ε0 S / C = 8.85 x 10^-12 x 3.14 x (0.40 x 10^-3)² / (100.0 x 10^-12) = 0.044 x 10^-6 m = 0.044 µm

1 Answers · Science & Mathematics · 15/12/2010