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C=Q/V C= capacitance Q= charge V= voltage 10v*5.6pF = 56 picocoulombs +q on one -q on the other

1 Answers · Science & Mathematics · 13/05/2011

this page worked for me. not my work so i can't take credit. http://www.cramster.com/physics-answers-5-644331-cpi0.aspx this would have been simple if it just asked for the amount of charge

1 Answers · Science & Mathematics · 13/02/2010

1st answer is correct with respect to the potential differences before and after doubling the separation. However, work is equal to the change in potential energy stored in the capacitor. PE = V^2C/2. The separation doubles...

4 Answers · Science & Mathematics · 25/08/2010

**pf**= mbullet*vbullet, so The option, "5.**pf**= mbullet*vbullet" is correct**pf**= 0.030*vbullet ------------------ 1 or**pf**^2 = 0...3 Answers · Science & Mathematics · 11/12/2012

Ok, remember your equations for waves : speed = lamba*frequency lamba = wavelenght speed = 3.5*0.7 = 2.45 m/s Hope that helps

2 Answers · Science & Mathematics · 21/04/2007

q = (capacitance)*(Voltage) Voltage = q/c = (.000,000,17C)/(.000,000.013F) = 13.07692 Volts

2 Answers · Science & Mathematics · 23/02/2016

1.)C= (ε0)*A/d 100*10^-12=(8.8*10^-12)*(100*10^-6)/d (1mm=10^-3m) d=8.8*10^-5 (B) 2.) B the geometry of the conductors 3.) B. The charges on the two plates will remain unchanged, but the voltage will become zero.

1 Answers · Science & Mathematics · 24/02/2014

Use the formula fo = 1 / (2*pi* sqrt(LC)) C= 2200*10^-12 L=50x10^-3

1 Answers · Science & Mathematics · 05/05/2012

By Q = CV =>Q = 13 x 10^-12 x 76 =>Q = 9.88 x 10^-10 C

2 Answers · Science & Mathematics · 02/10/2010

While in air, the weight of the drop of oil dominates the force of surface tension. But inside the mixture the weight is neutralised by the upthrust. Thus the only force remaining unbalanced is the force of surface tension. So under the action of this force the...

2 Answers · Science & Mathematics · 31/03/2011