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...x 1000 = kVA. You also need to know how much you want to improve the

**PF**. Then use the following web site to compute the capacitor kVAr...3 Answers · Science & Mathematics · 20/06/2008

... as farads. The answer is 17683.8826 ohms. 300

**pf**is 0.0003 mf Use the following formula XC = 1 / (2...4 Answers · Science & Mathematics · 06/05/2013

Even if

**PF**is not corrected. KW is not KVA.1 Answers · Science & Mathematics · 13/05/2012

With no load, the power factor of a transformer is very low, but it not zero. The current always has a real component because of power losses in the transformer. The copper losses go down in proportion to current squared, but the iron losses are not...

2 Answers · Science & Mathematics · 16/06/2013

3000

**pF**, 0.0089 µF, 12000**pF**, and 0.024 µF or, ...1 Answers · Science & Mathematics · 23/02/2012

Dont ruin the meter

3 Answers · Science & Mathematics · 20/11/2013

No principal difference from the connection.

2 Answers · Science & Mathematics · 03/09/2013

q=c/v so answer will be 10nc

2 Answers · Science & Mathematics · 23/04/2013

1000pF I build capacitor and resistor part numbers all day long!!

9 Answers · Science & Mathematics · 03/04/2007

sure it is working, you just need to keep track of units - in metric system, unit of length is meter, not cm, mm, km etc. so A=0.03x0.03=0.0009 m^2 D=0.0007 m ε0 ≈ 8.854187817620... × 10−12 F/m or ε0 ≈ 0.000000000008854187817620 F/m you get C=1.1384x10...

4 Answers · Science & Mathematics · 23/12/2012