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  1. ½CV² = ½Li² -----> i = V*√(C/L) = 4.77*√(11.4e-12/0.0099) = 0.1619ma

    2 Answers · Science & Mathematics · 01/04/2018

  2. I don't know where you live, but generally "overtime" is 1.5 x ordinary time and "double time" is 2 x ordinary time, as it suggests. So to convert either back into ordinary rates, you divide by 1.5 or by 2. e.g. Number 7, overtime is $16.05, so ordinary time...

    1 Answers · Science & Mathematics · 25/02/2015

  3. a) Let f = the frequency (in Hertz) Let Z = the complex impedance Z = Zr + i(Zl - Zc) Zr = 8.3x10³ Zc = 1/{(2πf)C} Zc = 1/{(2πf)100x10^-12} Zc = 1.59x10^9/f Zl = (2πf)L Zl = (7...

    2 Answers · Science & Mathematics · 08/11/2014

  4. ...2)*(R) = [(2.5^2)A]*(28 Ohms) = 175 Watts = (VA)*(pf) Apparent power (VA) = power/pf = 175W/.7 = 250VA...

    2 Answers · Science & Mathematics · 18/05/2014

  5. ...nought = 8.854 x 10^(-12) F/m K = 3.70 Capacitance = 11.33 pF Q = VC = (19.90 V)(11.33 pF) = 225 picocoulombs...

    1 Answers · Science & Mathematics · 26/01/2014

  6. Note 0.02 uF = 20nF = 20,000 pF when searching make sure that you know if it is ceramic, or a poly type...

    4 Answers · Science & Mathematics · 16/10/2013

  7. a) P=V*I=110V * 8A = 880W b, c) if the toaster was running continuously (?) then it would consume E=P*t= 880W * 30 day * (24h/day) = 633600 Wh = 633.6 kWh note, 1h=3600seconds E=P*t = 633600Wh * 3600...

    1 Answers · Science & Mathematics · 02/05/2013

  8. ... = 3 x 10^6 VA E(no-load) = E(line-line) = 12488 V pf(load) =0.8 lagging Solving for I: I = S/...

    2 Answers · Science & Mathematics · 20/04/2013

  9. ωL=1/ωC C=1/ω^2L = 1/(2*3.14*105.6*10^6)^2*0.2*10^-6= 11.357[pF]

    1 Answers · Science & Mathematics · 01/04/2013

  10. ωL=1/ωC C=1/ω^2L = 1/(2*3.14*103.6*10^6)^2*0.2*10^-6= 11.8[pF] I don't know of another question.

    2 Answers · Science & Mathematics · 04/04/2014

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