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  1. ...1530000π)² C = (1/0.0011) (1/1530000π)² = 3.9e-11 F or 39 pF

    3 Answers · Science & Mathematics · 21/11/2019

  2. capacitance C = εo*εr* A / d since εo = 8.85*10^-12 and εr = 1 (pure air in between) , then : C = 8.85*10^-12*(5.25/3.14)*10^-1 = 1.48*10^-12 ( 1.48 pF )

    2 Answers · Science & Mathematics · 18/08/2019

  3. Assuming all three wires are made out of the same material you can determine the total (equivalent) resistance of the parallel wires using V=IReq and from there you can determine the total resistance of each wire using the parallel resistance equation. 1/Req...

    1 Answers · Science & Mathematics · 28/04/2019

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