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  1. ...so it must slow down at twice the rate -- a' = -31 m/s² (but you might not need the sign -- it might be understood). c. Well, it reaches velocity...

    1 Answers · Science & Mathematics · 11/05/2020

  2. 3.11×10^9  (even if it were correct) loses you a mark for ‘missing unit’. (a) The centripetal and resultant force are the same thing in this situation, so we just need to find the centripetal force: F = mv²/r = 9.11*10^-31 * (2.29*10^6...

    2 Answers · Science & Mathematics · 06/05/2020

  3. A) PE in m2 gets converted into KE for both masses: 3kg * 9.8m/s² * 0.97m = ½ * (3.70+3)kg...

    1 Answers · Science & Mathematics · 05/05/2020

  4. (b) the solution for this has the form v(t) = V_t * [1 - e^(-bt/m)] so you need 0.632*V_t = V_t * [1 - e^(-1.82*t / 0.00320) which solves to...

    1 Answers · Science & Mathematics · 30/04/2020

  5. ... a = F/m = (kR – Av²)/m (positive when speeding-up, negative when slowing down) When at a steady speed, a=0 so kR...

    4 Answers · Science & Mathematics · 05/06/2020

  6. ...0 + 2 x a x 90 =>a = 40.14 m/s^2 Thus the force required for take off will be By F(t) = ma =>F(t) = 2.3 x 10^4 x 40...

    3 Answers · Science & Mathematics · 10/04/2020

  7. ...little tougher... I hope I'm right... You need to figure out where the torque of the applied force <... force * h = Normal force * 1.10m Solve for h h = 1.10m/0.70 = 1.6m

    2 Answers · Science & Mathematics · 27/02/2020

  8. 1) Acc = speed/time = 92/13 = 7.1 m/s/s

    1 Answers · Science & Mathematics · 10/02/2020

  9. ... for t and then double it (up then down). I'll leave that for you if you're interested. iii) Now I think we WILL need to find the maximum height. H = h0 + v² / 2g = 3m + (25m/s)² / 19...

    3 Answers · Science & Mathematics · 08/02/2020

  10. ...h*f = hc/wl where f = frequency, wl = wavelength of photon, c = speed of light and h = unknown Planck constant. Now...  where W = work function of Cesium For wl = wl2 = 200nm, the electron has 4.11 eV of...

    1 Answers · Science & Mathematics · 06/02/2020

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