Sort by

- Relevance
- |Time

...so it must slow down at twice the rate -- a' = -31 m/s² (but you might not

**need**the sign -- it might be understood). c. Well, it reaches velocity...1 Answers · Science & Mathematics · 11/05/2020

3.11×10^9 (even if it were correct) loses you a mark

**for**‘missing unit’. (a) The centripetal and resultant force are the same thing in this situation, so we just**need**to find the centripetal force: F = mv²/r = 9.11*10^-31 * (2.29*10^6...2 Answers · Science & Mathematics · 06/05/2020

A) PE in m2 gets converted into KE

**for**both masses: 3kg * 9.8m/s² * 0.97m = ½ * (3.70+3)kg...1 Answers · Science & Mathematics · 05/05/2020

(b) the solution

**for**this has the form v(t) = V_t * [1 - e^(-bt/m)] so you**need**0.632*V_t = V_t * [1 - e^(-1.82*t / 0.00320) which solves to...1 Answers · Science & Mathematics · 30/04/2020

... a = F/m = (kR – Av²)/m (positive when

**speeding**-up, negative when slowing down) When at a steady**speed**, a=0 so kR...4 Answers · Science & Mathematics · 05/06/2020

...0 + 2 x a x 90 =>a = 40.14 m/s^2 Thus the force required

**for**take off will be By F(t) = ma =>F(t) = 2.3 x 10^4 x 40...3 Answers · Science & Mathematics · 10/04/2020

...little tougher... I hope I'm right... You

**need**to figure out where the torque of the applied force <... force * h = Normal force * 1.10m Solve**for**h h = 1.10m/0.70 = 1.6m2 Answers · Science & Mathematics · 27/02/2020

1) Acc =

**speed**/time = 92/13 = 7.1 m/s/s1 Answers · Science & Mathematics · 10/02/2020

...

**for**t and then double it (up then down). I'll leave that**for**you if you're interested. iii) Now I think we WILL**need**to find the maximum height. H = h0 + v² / 2g = 3m + (25m/s)² / 19...3 Answers · Science & Mathematics · 08/02/2020

...h*f = hc/wl where f = frequency, wl = wavelength of photon, c =

**speed**of light and h = unknown Planck constant. Now... where W = work function of Cesium**For**wl = wl2 = 200nm, the electron has 4.11 eV of...1 Answers · Science & Mathematics · 06/02/2020