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1. ### (need answer in 2 days please).You throw a javelin at a speed of 23 m/s at an angle of 40° above the horizontal.?

...)² / (2 * 9.81) m = 11 m ==== b. Refer to the diagram below for parts b and c. Consider the vertical motion (uniform acceleration motion...

1 Answers · Science & Mathematics · 31/12/2019

2. ### How fast would a golf ball fall if dropped from an airplane? In MPH. How long to reach that speed?

...10^-3*10^3*10 V = √ 21.4*16/3*10 ≅ 34 m/sec = 76 MPH the time needed for reaching that speed is nearly 3 times the time taken in vacuum , i.e. 3*34/10...

3 Answers · Science & Mathematics · 29/11/2019

3. ### Hi guys, i need a bit of help with an physics assigment ( can't solve it and my brother needs it for tomorrow)?

f’ = observed frequency f = source frequency v = speed of sound vₛ = source’s speed= 72 km/h = 20m/s v₀ = observer’s speed = 32km...

3 Answers · Science & Mathematics · 17/09/2019

4. ### Consider an elevator car (lift) with a mass of 700kg which call carry up to 600kg of passengers. Use g = 10ms^-2.?

The speed is not needed for the total energy required if any gain in kinetic energy at the beginning is used in permitting the elevator to coast to a stop. E = mgh = ( 700+600)*10 * 9 = 117 kJ approximately.

2 Answers · Science & Mathematics · 15/08/2019

5. ### Exercise physics need help?

... be reachable by the bullet. Let's say the bullet is in the air for time "t." If the bullet is just able to reach the car, impact...

2 Answers · Science & Mathematics · 10/07/2019

6. ### Does RPM vary linearly with the speed of an airplane?

... a = F/m = (kR – Av²)/m (positive when speeding-up, negative when slowing down) When at a steady speed, a=0 so kR...

4 Answers · Science & Mathematics · 05/06/2020

7. ### Take Off. A Navy jet with a mass of 2.3 x 104 kg requires an airspeed of 85 m/s for liftoff. ?

...0 + 2 x a x 90 =>a = 40.14 m/s^2 Thus the force required for take off will be By F(t) = ma =>F(t) = 2.3 x 10^4 x 40...

3 Answers · Science & Mathematics · 10/04/2020

8. ### Physics help!! While sitting on a tree branch 12 m above the ground, you drop a chestnut. When the chestnut has fallen 2.0 m?

Now find the time time for first nut to fall to the ground. 12=1/2 g t^2. Time to fall...nut cover the distance. s=vo(t-t1) +1/2 g(t-t1)^2= 1/2 g t^2 Now solve for v0, the initial velocity of the second nut.

1 Answers · Science & Mathematics · 12/09/2019

9. ### I need physics help?

0 = 24m + (7 m/s)t - (1/2)(9.8 m/s^2)t^2 => 4.9 t^2 - 7 t - 24 = 0 => t = use quadratic formula and pick only the positive answer for t.

3 Answers · Science & Mathematics · 14/10/2019

10. ### What happens if gravity accelerates a object to a speed faster than light?

... following is the General Relativity equation for 4-acceleration: aᵏ = d²xᵏ⁄dτ² = -⌈ᵏᵤᵥ(...

9 Answers · Science & Mathematics · 04/11/2019