Yahoo Web Search

  1. Ads
    related to: Mississippi Riverboat Trips
  1. Speed of the boat in still water = u kph Speed of the water current = v kph Distance traveled = d = 30 km Time taken to travel downstream = t1 = 3 hr Time taken to travel upstream = t2 = 5 hr We have the following...

    1 Answers · Science & Mathematics · 22/11/2013

  2. Let speed of boat in still waters be x km / hour and speed of current be y km/ hour DOWNSTREAM ------------------------- SPEED = DISTANCE / TIME ( x+ y ) = 70/5 = 14 .............(A) UPSTREAM -------------------- SPEED...

    2 Answers · Science & Mathematics · 27/04/2013

  3. Call s1= speed of riverboat s2= speed of current We have system of linear equation: (1) (s1 + s2)*3=30...

    2 Answers · Science & Mathematics · 25/02/2013

  4. Sounds great! No spelling errors

    2 Answers · Arts & Humanities · 21/03/2012

  5. d = rt let V km/h = rate of boat & v km/h that of stream, then (V+v)*3 = 30 or V+v = 10 (V-v)*5 = 30 or V-v = 6 adding, 2V = 16, V = 8 ans: 8 km/h ------

    1 Answers · Science & Mathematics · 24/08/2011

  6. ..., Steamboat Natchez Riverboat Cruise(don't eat there the food is terrible),Moonwalk on the Mississippi , Audubon Zoo, Aquarium...

    2 Answers · Travel · 08/06/2011

  7. ... made the trip faster and ...1840 steam-powered riverboats and steamboats...and down the Ohio, Mississippi and Missouri...

    2 Answers · Science & Mathematics · 22/05/2011

  8. ..., Steamboat Natchez Riverboat Cruise(don't eat there the food is terrible),Moonwalk on the Mississippi , Audubon Zoo, Aquarium...

    1 Answers · Travel · 16/05/2011

  9. ..., Steamboat Natchez Riverboat Cruise(don't eat there the food is terrible),Moonwalk on the Mississippi , Audubon Zoo, Aquarium...

    6 Answers · Travel · 11/05/2011

  10. ..., Steamboat Natchez Riverboat Cruise(don't eat there the food is terrible),Moonwalk on the Mississippi , Audubon Zoo, Aquarium...

    2 Answers · Travel · 12/04/2011

  1. Ads
    related to: Mississippi Riverboat Trips
  1. Try asking your question on Yahoo Answers