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related to: MUO

B =

**muo**x n x i => i = B/**muo**n where**muo**= 4pi x 10^-7; n = no. of turns per unit length; B = magnetic field induction i = 0.30/(4pix10^-7x1200/0.75) => i = 149.2A2 Answers · Science & Mathematics · 03/04/2013

B at the center of solenoid =

**muo**x n x i = 4pi x 10^-7 x 1400 x 3.4 = 6x10^-3T Torque = BANi = 6x10^-3x1.2x10^-3x56x0.55 = 2.2x10^-4Nm2 Answers · Science & Mathematics · 18/03/2013

.../m) mu0 - permeability of vacuum (air) = 4*pi*10^-7 H/m B = H*

**muo**- magnetic induction .........(1) R - distance from antenna = 10^5 m r - radius of of...2 Answers · Science & Mathematics · 17/04/2007

Hello Nicole, let us the expression B = (

**muo**/ 2 pi) * (I / d) Here B = 1.47*10^-8 T, d = 8.91*10...1 Answers · Science & Mathematics · 15/10/2012

...magnetic field induction at P2 is got by the formula B = (

**muo**/4pi) (i/R) (sin@1+sin@2)**muo**= 4pi*10^--7 H/m; i = 0.556 A...1 Answers · Science & Mathematics · 09/12/2009

...would be more intense only along the axis of the solenoid. Its induction B =

**muo**n i. Where**muo**= 4 pi *10^--7 H/m. n - the number of ...1 Answers · Science & Mathematics · 30/04/2010

... formula for parallel wires carrying current=(B*2*pi*r)/

**muo**where B=magnitude of magnetic field =280 µT converting to...1 Answers · Science & Mathematics · 16/04/2015

Use the equation: B=

**muo**I/2piR so I=2piRB/**muo**2 Answers · Science & Mathematics · 17/06/2011

...field of induction intensity B, there is an energy density U = 1/(2*

**muo**) * B^2**muo**is the magnetical permitivity of the vacuum If ...2 Answers · Science & Mathematics · 19/06/2009

...wire), you can easily use the Ampere's theorem: B*2*Pi*d =

**muo**I1 giving B=**muo**I1 / (2 Pi d) Then...4 Answers · Science & Mathematics · 15/08/2012